Answer:
$24,890.46, $25,109.59
Step-by-step explanation:
Given:
n = 48, the sample size
m = $25,000, th sample mean
σ = $3000, the maximum variance
The standard deviation is
s = √σ = √(3000) = 54.772
As a rule of thumb, the range is 4 times the standard deviation. Therefore the range is
R = 4*54.772 = 219.09
Half the range is
R/2 = 219.09/2 = 109.45
The required range is
(25000-109.45, 25000+109.45) = (24890.46, 25109.54)
Answer: $24,890.46, $25,109.54
Let the speed of El Toro be x mph and that of T Express be y mph.
Given : Speed of El Toro > Speed of T Express
i.e, x > y
Also, the difference in the speeds of El Toro and T Express is 5 mph.
So, the required equation is
x - y = 5
To determine the speed of a train, the speed of other is required.
The speed of El Toro = Speed of T Express + 5
The speed of T Express = Speed of El Toro - 5
Answer:
1.5
Step-by-step explanation:
The question is incomplete due to the probability distribution table, investigating you can find it so I will attach it.
Having the table, we need to find the mean of the probability distribution, which is defined as the sum of the product of probability and value of random distribution, that is:
M = Sum (xi) * P (xi)
We replace:
M = 0.5 * 0.07 + 1 * 0.2 + 1.5 * 0.46 + 2 * 0.2 + 2.5 * 0.07
M = 1.5
Therefore, the mean of the given table is 1.5
Answer: 23.5m
Step-by-step explanation:
Answer:
this should be correct, im sorry im wrong.
Step-by-step explanation: