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2 years ago

11

Question 3 of 10

1 answer:

Trava [24]2 years ago

7 0

Answer:

A

Step-by-step explanation:

On Monday 4 people signed up plus the 11 who agreed to go the following day

which adds up to 15

You might be interested in

Which of the following is the solution to the following system of inequalities?

seropon [69]

It is 30 bc u dived then subtract

5 0

3 years ago

A zookeeper is monitoring the population of gazelles. The herd needs three times more males than females to thrive, and the zoo

avanturin [10]

Answer:

0 < x ≤ 12 and 0 < y ≤ 36

Step-by-step explanation:

Here, x represents the number of female gazelles and y represents the number of male gazelles.

The zoo only has room for 12 female gazelles.

∵ The number of rooms must be more than or equal to the total female gazelles ,

12 ≥ x

Also, number of animals can not be negative,

And, it must be greater than 0.

⇒ 0 < x ≤ 12,

⇒ 3(0) < 3x ≤ 3(12)

⇒ 0 < 3x ≤ 36

∵ Number of males gazelles = 3 × number of female gazelles

⇒ y = 3x

⇒ 0 < y ≤ 36

Hence, the constraints to represent a thriving population of gazelles at the zoo are,

0 < x ≤ 12,

0 < y ≤ 36

7 0

3 years ago

Read 2 more answers

2/5+3/7 is the same as?

Vsevolod [243]

Answer:

29/35

Step-by-step explanation:

Least common denominator of 5 and 7 is 35

$\frac{2}{5}=\frac{2*7}{5*7}=\frac{14}{35}\\\\\frac{3}{7}=\frac{3*5}{7*5}=\frac{15}{35}\\\\\frac{2}{5}+\frac{3}{7}=\frac{14}{35}+\frac{15}{35}\\\\ \ = \frac{14+15}{35}\\\\ = \frac{29}{35}$

6 0

3 years ago

The diameter of a circle is 8 kilometers. What is the angle measure of an arc kilometers long?

inn [45]

Answer: 14.32 degrees

The circle has a diameter of 8 kilometers, so the perimeter would be:
perimeter= pi * diameter
perimeter= 22/7 * 8 kilometers= <span>25.14 kilometers

A full perimeter </span>of the circle, which is 25.14km, has 360° angle. So 1km arc would be: 1km/ 25.14 km * 360°= 14.32°

7 0

3 years ago

Plot the point whose polar coordinates are given. Then find two other pairs of polar coordinates of this point, one with r >

Ira Lisetskai [31]

Answer:

The other pairs are:

$(a)\ (2, \frac{5\pi}{6}) \to$ $(2, \frac{17\pi}{6})$ and $(-2, \frac{23\pi}{6})$

$(b)\ (1, -\frac{2\pi}{3}) \to$ $(1, \frac{4\pi}{3})$ and $(-1, \frac{7\pi}{3})$

$(c)\ (-1, \frac{5\pi}{4}) \to$ $(-1, \frac{3\pi}{4} )$ and $(1, \frac{7\pi}{4})$

See attachment for plots

Step-by-step explanation:

Given

$(a)\ (2, \frac{5\pi}{6})$

$(b)\ (1, -\frac{2\pi}{3})$

$(c)\ (-1, \frac{5\pi}{4})$

Solving (a): Plot a, b and c

See attachment for plots

Solving (b): Find other pairs for $r > 0$ and $r < 0$

The general rule is that:

The other points can be derived using

$(r, \theta) = (r, \theta + 2n\pi)$

and

$(r, \theta) = (-r, \theta + (2n + 1)\pi)$

Let $n =1$ ---- You can assume any value of n

So, we have:

$(r, \theta) = (r, \theta + 2n\pi)$

$(r, \theta) = (r, \theta + 2*1*\pi)$

$(r, \theta) = (r, \theta + 2\pi)$

$(r, \theta) = (-r, \theta + (2n + 1)\pi)$

$(r, \theta) = (-r, \theta + (2*1 + 1)\pi)$

$(r, \theta) = (-r, \theta + (2 + 1)\pi)$

$(r, \theta) = (-r, \theta + 3\pi)$

$(a)\ (2, \frac{5\pi}{6})$

$r = 2\ \ \ \ \theta = \frac{5\pi}{6}$

So, the pairs are:

$(r, \theta) = (r, \theta + 2\pi)$

$(2, \frac{5\pi}{6}) = (2, \frac{5\pi}{6} + 2\pi)$

Take LCM

$(2, \frac{5\pi}{6}) = (2, \frac{5\pi+12\pi}{6})$

$(2, \frac{5\pi}{6}) = (2, \frac{17\pi}{6})$

And

$(r, \theta) = (-r, \theta + 3\pi)$

$(2, \frac{5\pi}{6}) = (-2, \frac{5\pi}{6} + 3\pi)$

Take LCM

$(2, \frac{5\pi}{6}) = (-2, \frac{5\pi+18\pi}{6})$

$(2, \frac{5\pi}{6}) = (-2, \frac{23\pi}{6})$

The other pairs are:

$(2, \frac{17\pi}{6})$ and $(-2, \frac{23\pi}{6})$

$(b)\ (1, -\frac{2\pi}{3})$

$r = 1\ \ \ \theta = -\frac{2\pi}{3}$

So, the pairs are:

$(r, \theta) = (r, \theta + 2\pi)$

$(1, -\frac{2\pi}{3}) = (1, -\frac{2\pi}{3} + 2\pi)$

Take LCM

$(1, -\frac{2\pi}{3}) = (1, \frac{-2\pi+6\pi}{3})$

$(1, -\frac{2\pi}{3}) = (1, \frac{4\pi}{3})$

And

$(r, \theta) = (-r, \theta + 3\pi)$

$(1, -\frac{2\pi}{3}) = (-1, -\frac{2\pi}{3} + 3\pi)$

Take LCM

$(1, -\frac{2\pi}{3}) = (-1, \frac{-2\pi+9\pi}{3})$

$(1, -\frac{2\pi}{3}) = (-1, \frac{7\pi}{3})$

The other pairs are:

$(1, \frac{4\pi}{3})$ and $(-1, \frac{7\pi}{3})$

$(c)\ (-1, \frac{5\pi}{4})$

$r = -1 \ \ \ \ \theta = \frac{-5\pi}{4}$

So, the pairs are

$(r, \theta) = (r, \theta + 2\pi)$

$(-1, \frac{-5\pi}{4}) = (-1, \frac{-5\pi}{4} + 2\pi)$

Take LCM

$(-1, \frac{-5\pi}{4}) = (-1, \frac{-5\pi+8\pi}{4} )$

$(-1, \frac{-5\pi}{4}) = (-1, \frac{3\pi}{4} )$

And

$(r, \theta) = (-r, \theta + 3\pi)$

$(-1, \frac{-5\pi}{4}) = (-(-1), \frac{-5\pi}{4}+ 3\pi)$

Take LCM

$(-1, \frac{-5\pi}{4}) = (1, \frac{-5\pi+12\pi}{4})$

$(-1, \frac{-5\pi}{4}) = (1, \frac{7\pi}{4})$

So, the other pairs are:

$(-1, \frac{3\pi}{4} )$ and $(1, \frac{7\pi}{4})$

5 0

3 years ago