Answer:
Counterclockwise 160°? I don't know what is being asked, but that's the total.
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
(x²)-³ =<u> 1 </u> = <u> 1 </u> = <u> 1 </u><u /> = <u> 1 </u>
(x²)³ (x²)(x²)(x²) x² + ²+ ² x^6
∠1 and ∠3 complementary,
∠1 = ∠2,
so
∠1 and ∠2 complementary.
Answer : C.
Answer:
1/6
Step-by-step explanation:
2/3 divided by 4= 2/3 x 1/4
2/3 x 1/4=2/12
2/12 simplifies to 1/6