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djyliett [7]
2 years ago
13

A child is playing a card game where, if she does not

Mathematics
1 answer:
ivann1987 [24]2 years ago
7 0

The probability of choosing the red card will be 0.03%

<h3>What is probability?</h3>

In this situation, Mickey should have drawn the first 7 cards that are not diamond and then on the 8th attempt she should draw an ace.

Let A be the event of drawing 7 cards which are not diamond and B the event of drawing an ace card. therefore the required probability is

P(A∩B)=P(A)*P(B)

Now, there are 13 diamonds and 39 other cards. Hence,

P(A)=(13/39)⁷=0.1335

After drawing 7 non-diamond cards, the 8th card must be a diamond. Hence,

P(B)=0.25

Hence, P(A∩B)=P(A)*P(B)=0.1335*0.25=0.033(approximately 0.03,i.e. 3%)

Therefore the probability that Mickey will draw her first red diamond on the 8th attempt is 0.03%

To know more about probability follow

brainly.com/question/24756209

#SPJ1

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The simplified expression of 6(y + 13) + 21y is 27y + 78

<h3>How to simplify the expression?</h3>

The expression is given as:

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