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Troyanec [42]
3 years ago
15

How do u do this???????

Mathematics
1 answer:
Zanzabum3 years ago
7 0
2x-y=60/100* 5y

2x-y= 6*5y/10

2x-y=3y
2x=3y+y
2x=4y     | :2 
x=2y   | :x

1=2y/x   :2

⇒ y/x= 1/2


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Write an equation to represent the relationship shown in the graph.<br> Use the graph below
Lostsunrise [7]

Answer:

y=x+3

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when the line crosses the y-axis)

First, we could determine the slope (<em>m</em>). The slope is the \displaystyle\frac{rise}{run} of the line, or the number of units it travels up over the number of units it travels to the right.

Notice how each consecutive point moves up 1 unit and right 1 unit. This makes the slope of the line 1/1, which is just 1:

y=1x+b\\y=x+b

Now, to find the y-intercept, we must identify the value of y when the line crosses the y-axis.

The line crosses the y-axis at y=3, so therefore, the y-intercept is 3:

y=x+3

I hope this helps!

6 0
2 years ago
What is the answer to -3x+2=-7
ycow [4]

Answer:

x=3

Step-by-step explanation:

-3x=-7-2=-9

x=-9/-3=3

4 0
3 years ago
Read 2 more answers
Can anyone explain how to get to the answer ? I’ll mark brainliest! Please
Svetllana [295]

Answer:

A

Step-by-step explanation:

It is linear because it is a pattern of adding 1 and not quadratic for there is no squaring. It is no exponential because the ratio stays the same.

7 0
3 years ago
What is 6 to the negitive 3rd power?
almond37 [142]
Get rid of negative exponents by remembering that x^-a= 1/x^a.

6^-3= 1/6^3

Evaluate the exponent
6^3= 216

Final answer: 1/216
5 0
3 years ago
Projectile Is shot upward from the surface of Earth with an initial velocity of 136 meters per second. Use the position
Anna007 [38]

Answer:

v(3\,s) = 106.6\,\frac{ft}{s}, v(15\,s) = -11\,\frac{ft}{s}

Step-by-step explanation:

The velocity function of the projectile is obtained by deriving the position function:

v(t) = -9.8\cdot t + 136

Now, the velocities after 3 and 15 seconds are, respectively:

v(3\,s) = -9.8\cdot (3) + 136

v(3\,s) = 106.6\,\frac{ft}{s}

v(15\,s) = -9.8\cdot (15) + 136

v(15\,s) = -11\,\frac{ft}{s}

6 0
3 years ago
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