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AleksAgata [21]
2 years ago
11

If Mrs. Hamm divides 7 pounds of potting soil equally into three flower pots, what is the weight of potting soil in one flower p

ot? A) 3 7 pound B) 7 3 pounds C) 3 1 7 pounds D) 7 1 3 pounds
Mathematics
1 answer:
Leno4ka [110]2 years ago
5 0

The weight of potting soil in one flower pot is 7/3 pounds or 2.34 pounds option (B) is correct.

<h3>What is a fraction?</h3>

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

We have total weight of the potting soil = 7 pounds

It is divided equally into three flower pots.

So each pot contains = 7/3 potting soil

Thus, the weight of potting soil in one flower pot is 7/3 pounds or 2.34 pounds option (B) is correct.

Learn more about the fraction here:

brainly.com/question/1301963

#SPJ1

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Can someone help me with this please....ill give points and brainless​
den301095 [7]

Answer:

The total surface area of the given cone is

S = 4( \sqrt{3}+1)\pi  cm^2

Step-by-step explanation:

<u>Step 1</u>:-

<u>Formula:-</u>

The total surface area of cone is

S.A = \pi r l +B

S.A = \pi r l +area of base

S.A = \pi r l+ \pi r^2........(1)

<u>Step 2:-</u>

Given slant height l = 2\sqrt{3} cm

and radius of the circle (base) = 2

substituting these values in equation (1)

S.A = \pi (2)(2\sqrt{3} ) + \pi (4)

on simplification, we get

S.A = \pi (4\sqrt{3}+4)

<u>Final answer</u> :-

S.A = 4 (\sqrt{3}+1)\pi cm^2

8 0
3 years ago
The monthly dues for a premium membership is $15 more than the cost of a standard membership. The premium membership cost $40 pe
77julia77 [94]
40.00 for premium - 15.00 more than standard
40-15=35.00 for standard
4 0
3 years ago
Daniel is training for a walk-a-thon. In the first week, he walked a total five miles. In the second week, he walked a total of
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3 years ago
How to describe partial products yo 4th grader
erastova [34]

To describe partial products in a "laymans" term, you'd have to set up an problem with the 4th grader.

Set it up in a big format and even make a game out of it with tiles on the floor.

Explain to the 4th grader that the number on the bottom will be multiplied by each number separately and then eventually added. For more than one digit multiplication problems, they add a "0" for each number they are on. Example: One zero after the first number is multiplied. Two zero's after the second number is multiplied, etc...

Then, you just add like normal.


I have actually used the tile method to help my 4th grader learn how to do partial products.

I suggest making BIG 8x10 numbers. Then, tape them (gently) on the floor. Have the 4th grader stand on the first number they'd be multiplying. Example:

12 x 6

The student would stand on the number 6. You then ask them to jump (or hop-just be careful of slippery surfaces) on the number they have to multiply with next; which would be the 2. You'd ask them, what is "6 x 2?". They should reply with 12.

Next, have another set of smaller numbers where they can come back and place the numbers. 2 would go on the bottom and they hold the 1 so they can remember they need to add it to the next multiplication number.

So, now you'd have them stand on the number 6 again. Ask where they have to multiply again. They should move to the 1. Ask what is "6x1". Then answer should be 6. Then remind them they are holding a number and what they should do with it. The answer should be "add it to the answer of the multiplication". So, it should be 6+1=7. Then, they'd place the number 7 at the bottom of the problem.

Once they figure it out with single digits, move onto double digits at the bottom and work up from there.  

This way, they are having to use BIG movements and will eventually gain muscle memory on which directions and how to multiple correctly.


GOOD LUCK!

3 0
3 years ago
Find the equation of the line in slope intercept form that has a slope of -2 and passes through the point (6,3). Demonstrate tha
DanielleElmas [232]

Answer:

y=-2x+15

Step-by-step explanation:

First, write out the equation in slope-intercept form, with what you already have:

y=-2x+b

Let "b" represent the y-intercept.

To find the y-intercept, substitute the point (6,3) in for the "x" and "y" variable of the equation and solve for "b":

3=-2(6)+b\\3=-12+b\\3+12=-12+12+b\\15=b

Therefore, your y-intercept is 15.

That means your equation is slope-intercept form <em>is</em> y=-2x+15.

8 0
3 years ago
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