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Brilliant_brown [7]
3 years ago
14

Daniel is training for a walk-a-thon. In the first week, he walked a total five miles. In the second week, he walked a total of

7 miles. In the third week, he walked a total of 9 miles. Based on his pattern, how many miles will he walk in the fourth week?​
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0
11. He’s increasing by 2 each week.
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Answer the question given above
suter [353]

Answer:

See explanation

Step-by-step explanation:

This is how you are suppoussed to solve it:

Measure each and every side of the rectangle with a ruler and add it. This would be your perimeter

This cannot be solved unless the page is infront of us.

5 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
3241004551 [841]

Answer:

Hold up i know the answer.

Step-by-step explanation:

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3 years ago
A principal of $5500 is invested in an account paying an annual rate of 7%. Find the amount in the account after 4 years if the
Colt1911 [192]

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Formulae is Future value, see in picture I've done example 1 for u.

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2 years ago
WORTH 98 POINTS
LUCKY_DIMON [66]

Answer:

The equation is -3x^2 + 30x + 225 = 0, and the number of days is 15.

Step-by-step explanation:

I assume an x is missing, and the function is h(x) = -3x^2 + 30x + 225

You want to know the number of days in which the function value is zero.

-3x^2 + 30x + 225 = 0

Divide both sides by -3.

x^2 - 10x - 75 = 0

(x - 15)(x + 5) = 0

x - 15 = 0 or x + 5 = 0

x = 15 or x = -5

We discard the negative solution.

Answer: The equation is -3x^2 + 30x + 225 = 0, and the number of days is 15.

5 0
4 years ago
The system of equations is given:
Nutka1998 [239]

Answer:

x=-1/85; y=-283/85; z=2/17

Step-by-step explanation:

Using an algebraic method like elimination or substitution would take a lot of steps which could lead to mistake the calculations. In this case, I decided to use the Gaussian elimination. We can express the system in matrix form as follows:

\left[\begin{array}{ccc}2&-4&6\\9&-3&1\\5&0&9\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}14\\10\\1\end{array}\right]

To begin the calculations, we write the system in augmented matrix form and use the Gaussian elimination:

\left[\begin{array}{ccccc}2&-4&6&|&14\\9&-3&1&|&10\\5&0&9&|&1\end{array}\right]

By applying the Gaussian elimination, the final matrix is the following:

\left[\begin{array}{ccccc}1&0&0&|&-1/85\\0&1&0&|&-283/85\\0&0&1&|&2/17\end{array}\right]

In order to verify the results, it´s enough to substitute the calculated values in the original equations to see if the equalities are correct. Here you can see the verification for all of the equations:

2(-1/85)-4(-283/85)+6(2/17)=14\\9(-1/85)-3(-283/85)+1(2/17)=10\\5(-1/85)+9(2/17)=1

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3 years ago
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