Pakal triangle is hard to do with long things, but it is easy up to like 5 degree
we look at the row for 5th degree (6th row)
the sequence is
1,5,10,10,5,1
that is the coeficients
for (a+b)^5 that is
1a^5b^0+5a^4b^1+10a^3b^2+10a^2b^3+5a^1b^4+1a^0b^5
see the exponents each time add to 5
so
1x^5(-5)^0+5x^4(-5)^1+10x^3(-5)^2+10x^2(-5)^3+5x^1(-5)^4+1x^0(-5)^5=
x^5-25x^4+250x^3-1250
The answer is 4/7, because if A to P is 3/7 of the way, going to B would be to the end. So, you have to go 4/7 of the way to get to the end.
Answer:
1. yes 2. no
Step-by-step explanation:
for #2 it would have to be 0.57 and 0.570
Answer:
C. 4.6
Step-by-step explanation:
If you subtract 3.0 from 1.4 you get 1.6, which is the can be added to 3.0 to find the missing value.
Answer:
127 7/9
Step-by-step explanation:
144 - 2/9
144/1 - 2/9
(144×9)−(2×1)/1×9
1296-2/9
1294/9
= 143 7/9
143 7/9 - 16
= 127 7/9
