Answer:
The value of the quantity after 87 months will be of 599.64.
Step-by-step explanation:
A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.
This means that the quantity, after t periods of 6 years, is given by:

What is the value of the quantity after 87 months, to the nearest hundredth?
6 years = 6*12 = 72 months
So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).


The value of the quantity after 87 months will be of 599.64.
$117.05
- $ 14.99
-------------
$102.46 left
Divide 102.46 by 0.81, and you get 126, which makes it 126 miles.
Hope this helps!
Answer:
<em>Choice: B.</em>
Step-by-step explanation:
<u>Operations With Functions</u>
Given the functions:
![f(x)=\sqrt[3]{12x+1}+4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4)

The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:

![(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%28%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4%29)
Operating:
![(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D-4)
Joining like terms:
![\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}](https://tex.z-dn.net/?f=%5Cboxed%7B%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D%2B2%7D)
Choice: B.
Answer:
One of the solution is 2
Step-by-step explanation: