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2 years ago

13

Find the missing digit for the following bank identification numbers:

2 answers:

Softa [21]2 years ago

6 0

Answer:

71100139<u>2</u>

321000<u>7</u>59

Step-by-step explanation:

hope it helps ^o^

NikAS [45]2 years ago

4 0

Type such digits that's are correlated to both numbers but they are not present in both rather than present in one.

They can be 2 and 7 or 5 and 9

711001392
321000756

You can write other one also

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What is the midpoint of a segment (-2,-7) and (7,4)

Rasek [7]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-7})\qquad
(\stackrel{x_2}{7}~,~\stackrel{y_2}{4})
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{7-2}{2}~~,~~\cfrac{4-7}{2} \right)\implies \left(\cfrac{5}{2}~,~\cfrac{-3}{2} \right)\implies \left( 2\frac{1}{2}~,~-1\frac{1}{2} \right)$

5 0

3 years ago

Write a phrase as an algebraic expression six less than a number times 11

nadezda [96]

Let the number = x

11x is 11 times the number. You are to take 6 less than this. Be careful how you read six less. It means the 6 is subtracted from the 11x

11x - 6 This is what you finally get.

7 0

3 years ago

PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST

UkoKoshka [18]

Answer:

I think 87.2% is the correct answer.

I think it will help you

6 0

2 years ago

Complete the table for the function

IgorLugansk [536]

Answer:

C

Step-by-step explanation:

y(x) = x^(1/3)+7

y(-8)=(-8)^(1/3)+7=5

y(-1)=(-1)^(1/3)+7=6

y(1)=(1)^(1/3)+7=8

y(8)=(8)^(1/3)+7=9

4 0

3 years ago

A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in

Oksi-84 [34.3K]

Answer: The concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

Compound X Compound Y

272 16400 3870

327 3990 6420

So, our equations becomes

$16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191$

By solving these two equations, we get that

$C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}$

Hence, the concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

5 0

3 years ago