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Ad libitum [116K]
4 years ago
13

What is the approximate distance between the points (-5, 1) and (-2, 3) on a coordinate grid?

Mathematics
2 answers:
kherson [118]4 years ago
4 0
B. The answers B. You welcome :D

Natasha2012 [34]4 years ago
3 0
It should be b. if im not mistaken 
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Martin and Linda live 855 miles apart. At the same time, they start driving toward each other on the same road. Linda’s constant
Alinara [238K]

If one is at a speed of 35 mph and the other 60, sum the speeds to work with just one number:

35 + 60 = 95mph

The formula for time is:

Time = Distance / Speed
Time = 855 / 95
Time = 9h (D.)


Hope it helped,

Happy homework/ study/ exam!

6 0
3 years ago
Read 2 more answers
Please solve number 11:(​
MrRa [10]

Answer:

Market price $400

Cost price $300

Step-by-step explanation:

MP: market price

CP: cost price

1. (MP x 0.9) - CP = 60

CP = 0.9MP - 60

2. MP - CP = 100

CP = MP - 100

0.9MP - 60 = MP - 100

MP - 0.9MP = 100 - 60

0.1MP = 40

MP = 400

Cost price = MP - 100 = 400 - 100 = 300

3 0
2 years ago
Pls help!!!!!!!!!!!!!!
Stella [2.4K]

Answer:

can I be marked BRAINLY whatever please

4 0
3 years ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
4 years ago
Read 2 more answers
David invested $1,000 what would that money grow to in 18 months at a 5.5% interest rate
Nataly [62]
Interest I  =  PRT /100     

P = $ 1000
R = 5.5% per annum
T = 18 months  = 18 /12 = 1.5 years.

I =  1000 * 5.5 * 1.5 /100

I =  $ 82.5

Amount = P + I  =  1000 + 82.5 = 1082.5.

Hence the it would have grown to $1082.5
4 0
3 years ago
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