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iren [92.7K]
3 years ago
6

Sanjeev ate 1/6 of cake he gave to his frend the remainder 1/5 how much did he keep​

Mathematics
2 answers:
liq [111]3 years ago
8 0

Step-by-step explanation:

= 1 - ( \frac{1}{6}  +  \frac{1}{5} )

= 1 - ( \frac{5}{30} +  \frac{6}{30}  )

= 1 -  \frac{11}{30}

=  \frac{30}{30}  -  \frac{11}{30}

=  \frac{19}{30}

So, he keeps \frac{19}{30}

adelina 88 [10]3 years ago
4 0

Answer:

Sanjeev kept 19/30 of his cake.

Step-by-step explanation:

So, if Sanjeev ate 1/6 of the cake there will be 5/6 of the cake left over.

He gave 1/5 of this 5/6 to his friend.

He did not give 1/5 of the entire cake, he gave 1/5 of the remainder of his cake, which was 5/6.

To solve this, we must first convert both fractions to the same denominator.

1/5 and 5/6 becomes 6/30 and 25/30

He gave away 6/30 of this 25/30

It is now clear that we must take away how much he gave away from the remainder of the cake.

25/30 subtract 6/30 becomes 19/30

We cannot simplify this.

Therefore, Sanjeev kept 19/30 of his cake.

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3 years ago
258,197-64,500 (show me how to round this and I will give brainliest!)
Mars2501 [29]

There are a variety of methods of performing this subtraction, and corresponding different methods of regrouping.

If you're taught (as I was) to do the subtraction right-to-left, then the first regrouping you need to do is when you try to subtract 500 from 100. You must regroup the 8 thousands and 1 hundred to 7 thousands and 11 hundreds. Then, when you subtract 5 hundreds, you end with 7 thousands and 6 hundreds.

The next regrouping you need to do is when you try to subtract 6 ten-thousands from 5 ten-thousands. You must regroup the 2 hundred-thousands and 5 ten-thousands to 1 hundred-thousand and 15 ten-thousands. Then, when you subtract 6 ten-thousands, you end with 1 hundred-thousand and 9 ten-thousands.

The end result is

... 258,197 - 64,500 = 193,697

_____

If you use an abacus or soroban or similar tool to help you keep track of the numbers, you were likely taught to do the subtraction left-to-right. In this case, the first regrouping  comes when you want to subtract 6 ten-thousands. Practitioners of this method know that -6 = -10 +4, so the number represented on the tool becomes (2-1) hundred-thousands and (5+4) ten-thousands plus the rest of the initial number, or 198,197 after subtracting the 6 ten-thousands.

The subtraction proceeds until you find you need to subtract 500 from 100. At this point, the tool is representing the partial result as 194,197. Again, if you practice this method, you know that -5 = -10 +5, so you reduce the thousands digit by 1 (to 3) and add 5 to the hundreds digit to get 193,697.

_____

An attempt is made to show the regroupings in the attachment. In each case there are two of them. However, working left-to-right, the result of the first subtraction of 6 ten-thousands is 19 ten-thousands, so you never actually write down anything else. Of course, if you're using an abacus or soroban, you don't write down anything—you simply change the position of the beads on the tool.

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4 years ago
The quotient of r and 19
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3 years ago
He local zoo has 23 animals it can take on visits to schools and other community centers. How many ways can the zoo directors ch
dlinn [17]

Answer:

207

Step-by-step explanation:

8 0
3 years ago
Of the three different types of horses on a ranch, 1/4 are Arabians, 2/5 are Thoroughbreds, and the rest are Morgan's. What frac
mars1129 [50]

Answer:

The fraction of horses that are Morgan's=17/20

Step-by-step explanation:

Step 1: Determine fraction for each breed

Arabians=1/4

Thoroughbreds=2/5

Morgan's=unknown

Step 2: Express each breed as a fraction of the total

Number of Arabians=fraction of Arabians×total number of horses

Let total number of horses be x

Arabians=(1/4)×x=1/4 x

Thoroughbreds=(2/5)×x=2/5 x

Morgans's=m

Step 3: Calculate fraction of Morgans

Total number of horses=Arabians+Thoroughbreds+Morgans

x=(1/4)x+(2/5)x+m

solve for m;

m=x-(1/4)x-(2/5)x

m=x-3/20x

m=17/20 x

The fraction of horses that are Morgan's=17/20

6 0
4 years ago
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