Answer:
x=4+root6x
Step-by-step explanation:
A(b)+16 = 16 larger than the product of a and b.
A jar of jelly beans contains 50 red gumballs , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly
select a jelly bean, then select another without
putting the first jelly bean back. What is the
probability that you draw two red jelly beans? This is Dependent because you didnt put the other jelly bean in thus changing the total nmber of jelly beans.
A jar of jelly beans contains 50 red gumballs<span> , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly select a jelly bean, then select another while replacing the first jelly bean back. What is the probability that you draw two red jelly beans? This is Independent because you put the other jelly bean in thus keeping the total number of jelly beans.</span>
Answer:
of wht?....................
<h3>
Answer: 126</h3>
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Work Shown:
Let x and y be the two numbers.
We're given x = 162 and the variable y is unknown.
We're also given LCM = 1134 and HCF = 18
So,
LCM = (x*y)/HCF
1134 = 162*y/18
1134 = (162/18)y
1134 = 9y
9y = 1134
y = 1134/9
y = 126
The other number is 126
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Notice that
showing that 18 is the highest common factor (HCF) of the numbers 162 and 126. This partially confirms the answer.
Now let,
- A = multiples of 162
- B = multiples of 126
So,
- A = 162, 324, 486, 648, 810, 972, 1134, 1296, ...
- B = 126, 252, 378, 504, 630, 756, 882, 1008, 1134, 1260, ...
We see that 1134 is in each list of multiples and the smallest such common item. So the lowest common multiple (LCM) of 162 and 126 is 1134. This helps fully confirm the answer.
