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3 years ago

The algebraic expression that represents 2 less than 3 of n is:

Mathematics

2 answers:

Sholpan [36]3 years ago

8 0

Answer:

Step-by-step explanation:

3 of n : 3n

2 less than : -2

Combine together :

<u>3n - 2</u>

Marysya12 [62]3 years ago

7 0

Answer:

Option A. 3(n-2)

Step-by-step explanation:

"2 less" - "subtract 2"

Then 3 of n - 3n

Hope helps -

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SashulF [63]

Answer:

8x + 3y = -47

Step-by-step explanation:

1. Use the y = mx + b form to find b:

$y=-\frac{3}{8} x+b\\-4=\frac{3}{8}(5)+b\\-32=15+8b\\-47=8b\\-\frac{47}{8} =b$

2. Plug in b for the new equation:

$y=-\frac{3}{8} x-\frac{47}{8}$

3. Get rid of the denominators and simplify everything into standard form

(ax + by = c)

$y=-\frac{3}{8} x-\frac{47}{8}\\8y=-3x-47\\3x+8y=-47$

5 0

3 years ago

Haysel practiced the flute for 1 hour and 10 minutes. She stoped at 6 20 for dinner. What time did she begin practicing?

pshichka [43]

5:20 is when she started

5 0

3 years ago

Read 2 more answers

The amount of time it takes Isabella to wait for the bus is continuous and uniformly distributed between 3 minutes and 17 minute

Arturiano [62]

Answer:

P(X>5) = 0.857

Step-by-step explanation:

Let X $\sim$ uniform(3.17)

$f(x) = \dfrac{1}{17-3} ; \ \ \ 3 \le x \le 17$

The required probability that it will take Isabella more than 5 minutes to wait for the bus can be computed as:

$P(X > 5) = \int ^{17}_{5} f(x) \ dx$

$P(X > 5) = \int ^{17}_{5} \dfrac{1}{17-3} \ dx$

$P(X > 5) =\dfrac{1}{14} \Big [x \Big ] ^{17}_{5}$

$P(X > 5) =\dfrac{1}{14} [17-5]$

$P(X > 5) =\dfrac{12}{14}$

P(X>5) = 0.857

6 0

3 years ago

The difference of two numbers is 16 the greater number is five less than four times a small number find the two numbers

Elis [28]

Answer:

The numbers are 23 and 7

Step-by-step explanation:

1. Set up the equations

Let x = the greater number

and y = the smaller number. Then

(1) x - y = 16

4y = 4 times the smaller number and

4y - 5 = 5 less than 4 times the smaller number. Then

(2) x = 4y - 5

You have a system of two equations:

$\begin{cases}(1) & x - y = 16\\(2) & x = 4y - 5\end{cases}$

2. Solve the equations

$\begin{array}{lrcll}(3) & 4y - 5 - y & = & 16 &\text{Substituted (2) into (1)}\\& 3y - 5 & = & 16 &\text{Simplified}\\ & 3y & = & 21 &\text{Added 5 to each side}\\(4) &y & = & \mathbf{7} &\text{Divided each side by 3} \\& x - 7 & = & 16 & \text{Substituted (4) into (1)}\\& x& = & \mathbf{23} & \text{Added 7 to each side}\\\end{array}$