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larisa [96]
3 years ago
10

Calculate the estimate of the mean height of the students in cm and explain your answer

Mathematics
1 answer:
Zolol [24]3 years ago
8 0

Step-by-step explanation:

we find the average height of each height first,

t¹= (120+124)/2

=244/2

=122

t²= (124+128)/2

t²= 252/2

t²= 126

t³= (128+132)/2

t³= 260/2

t³= 130

t⁴= (132+136)/2

t⁴= 268/2

t⁴ =134

t⁵= (136+140)/2

t⁵= 276/2

t⁵= 138

so multiplying each height by its frequency we can find the total height, so we have..

total height= (122*7)+(126*8)+(130*13)+(134*9)+(138*3)

= 854+1008+1690+1206+414

= 5172

mean height = total height/total frequency

= 5172/40

=129.3

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A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc
Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 2x.

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

6\%=\frac{6}{100}=0.06

10\%=\frac{10}{100}=0.10

Amount of interest earned from lower-yielding account: 2x(0.06)=0.12x.

Amount of interest earned from higher-yielding account: x(0.10)=0.10x.

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0.22x=6600

\frac{0.22x}{0.22}=\frac{6600}{0.22}

x=30,000

Therefore, the man invested $30,000 at 10%.

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8 0
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Please please answer this correctly I have to finish this today as soon as possible
Simora [160]

Answer:

Step-by-step explanation:

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Next go half a box to the right and two boxes up, and plot your point there. that is (.5,2).

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yulyashka [42]
I disagree. The first one is false. No exponent rules apply if the bases AND the exponents are different.

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vivado [14]

Answer:

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Step-by-step explanation:

we have

f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}

g(x)=\frac{1}{x^{2}+1}

we know that

In the function

f(g(x))

The variable of the function f is now the function g(x)

substitute

f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}

f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}

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