According to the fundamental theorem of algebra, which polynomial function has exactly 6 roots? f (x) = 5 x superscript 4 baseli

Question

2 years ago

8

According to the fundamental theorem of algebra, which polynomial function has exactly 6 roots? f (x) = 5 x superscript 4 baseli

ne 10 x squared 2 f (x) = 5 x superscript 5 baseline 3 x superscript 4 baseline 12 x cubed 7 x squared minus 2 x 15 f (x) = 6 x superscript 5 baseline x cubed minus 4 x squared x minus 5 f (x) = 7 x superscript 6 baseline 3 x cubed 12

Mathematics

1 answer:

Yanka [14] · Answer 1 · 2023-01-11T23:32:28+03:00

The polynomial function has exactly 6 roots is f(x) = 7x⁶ + 3x³ + 12. Then the correct option is D.

<h3>What is Algebra?</h3>

Algebra is the study of mathematical symbols and the rule involves manipulating these mathematical symbols.

According to the fundamental theorem of algebra.

The polynomial function has only exactly 6 roots.

The roots are the value of the variables in the polynomial at which the value of the polynomial is zero.

If the degree of the variable is n then the number of the roots will be n or less than n.

If the number of the roots are 6, then the degree of the variable will be 6 in the polynomial.

Then the polynomial function has exactly 6 roots is f(x) = 7x⁶ + 3x³ + 12.

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ1