(1+x^2)^8
=(1+8x^2+8*7/(1*2)x^4+8*7*6/(1*2*3)x^6+8*7*6*5/(1*2*3*4)x^8+....)
=1+8x^2+28x^4+56x^6+70x^8+....)
For x<1, higher power terms diminish in value, hence we can approximate powers of numbers.
1.01=(1+0.1^2) => x=0.1 in the above expansion
(1.01)^8
=1+8(0.1^2)+28(0.1^4)+56(0.1^6) [ limited to four terms, as requested]
=1+0.08+0.0028+0.000056 (+0.00000070)
=1.082856 (approximately)
Answer:
A reflection
Step-by-step explanation:
It has been mirrored.
Answer:
91
Step-by-step explanation:
Let
x = first number
x+1 = second number
x+2 = third number
x+3 = fourth number
Total = 182
x + x + 1 + x + 2 + x + 3 = 182
4x + 6 = 182
Subtract 6 from both sides
4x + 6 - 6 = 182 - 6
4x = 176
Divide both sides by 4
x = 176 / 4
= 44
x = 44
x = 44
x+1 = 44 + 1 = 45
x+2 = 44 + 2 = 46
x+3 = 44 + 3 = 47
Sum of the two middle numbers = 45 + 46
= 91
Answer:
x=8
Step-by-step explanation:
-4 = 12 - 2x
when plus 12 goes to the left hand side it changes its sign so,
-4 -12 = -2x
- * - is plus so add 4 and 12 but keep the sign - because 12 is the greatest number and its sign is -
-16=-2x
when -2 comes to the left hand side it changes its from multiplication to division.So,
-16/-2=x
8=x
we will get positive 8 because minus and minus also gets cancel.
