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egoroff_w [7]
2 years ago
9

Write an expression for the sequence of 10 increased by the sum of 9 and n

Mathematics
1 answer:
gregori [183]2 years ago
8 0

Answer:

10 + (9 + n) = ?

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Find the sum of 3b/b 2 and 12/b 2 and express it in simplest form
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\frac{3b}{b^{2}} + \frac{12}{b^{2}} = \frac{3b + 12}{b^{2}} = \frac{3(b) + 3(4)}{b^{2}} = \frac{3(b + 4)}{b^{2}}
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How to graph from linear standered form 2x-6y=12?​
Alexus [3.1K]

Answer:

See graph below for answer

Step-by-step explanation:

Step 1) Change to y-intercept form

6y = 2x - 12

y = 1/3x - 2

Step 2) Graph.

See graph below for answer

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Read 2 more answers
A soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while
bija089 [108]

Answer:

The probability that the assembly line will be shut down is 0.00617.

Step-by-step explanation:

We are given that a soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while 1% is not within specification.

Every hour, 12 random bottles are taken from the assembly line and tested. If 2 or more bottles in the sample are not within specification, the assembly line is shut down for recalibration.

Let X = <u><em>Number of bottles in the sample that are not within specification</em></u>.

The above situation can be represented through binomial distribution;

P(X=r)=\binom{n}{r} \times p^{r}\times (1-p)^{n-r};x=0,1,2,3,.....

where, n = number of trials (samples) taken = 12 bottles

             x = number of success  = 2 or more bottles

            p = probabilitiy of success which in our question is probability that  

                 bottles are not within specification, i.e. p = 0.01

So, X ~ Binom (n = 12, p = 0.01)

Now, the probability that the assembly line will be shut down is given by = P(X \geq 2)

  P(X \geq 2) = 1 - P(X = 0) - P(X = 1)

                 = 1-\binom{12}{0} \times 0.01^{0}\times (1-0.01)^{12-0}-\binom{12}{1} \times 0.01^{1}\times (1-0.01)^{12-1}

                 = 1-(1 \times 1\times 0.99^{12})-(12 \times 0.01^{1}\times 0.99^{11})

                 = <u>0.00617</u>

8 0
3 years ago
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