1 year ago

Please help me I need assistance

1 answer:

3 0

$(\stackrel{x_1}{2}~,~\stackrel{y_1}{-15})\qquad (\stackrel{x_2}{14}~,~\stackrel{y_2}{r}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{r}-\stackrel{y1}{(-15)}}}{\underset{run} {\underset{x_2}{14}-\underset{x_1}{2}}}~~ = ~~\stackrel{\stackrel{m}{\downarrow }}{\cfrac{3}{4}}\implies \cfrac{r+15}{12}~~ = ~~\cfrac{3}{4}\implies r+15 = \cfrac{12\cdot 3}{4} \\\\\\ r+15=9\implies \boxed{r=-6}$

You might be interested in

What is 13 nickels combined with 6 dimes?

Setler [38]

125 = 6 dimes = 60 and 13 nickles = 65

60+65= 125

Hope i was the brainliest asnwer.

6 0

2 years ago

Question 4 (2 points)

Law Incorporation [45]

Answer:

x= $19.25 + $36

y= total cost

Step-by-step explanation:

x= number of nights + admission

y= total cost

7 0

2 years ago

Freemont Run Club surveyed a random sample of 30 members about their running habit. Of the members surveyed, 9 said that they ru

atroni [7]

Answer:

i think its 420

Step-by-step explanation:

8 0

2 years ago

A particle moves on a line away from its initial position so that after t hours it is s = 2t^2 +3t miles from its initial positi

Vaselesa [24]

Answer:

Average speed of the particle is 13 miles per hour.

Step-by-step explanation:

From the given question expression for distance traveled by the particle is

$s=2t^{2}+3t$

Then fro the time interval (1, 4) we have to calculate the average speed.

At t=1, s=2(1)²+3(1) =2+3 =5 miles

And at t = 4 s=2(4)²+3(4) = 2(16)+12 = 32+12 =44 miles

So displacement of the particle in the time span from 1 to hours.

s = (44-5) = 39 miles

And the times taken = (4-1) =3 hours

From the formula speed = displacement/(time taken for displacement)

V = 39/3 = 13 miles/hour

4 0

3 years ago

What ratio is equivalent to 5 to 4

r-ruslan [8.4K]

8:10 16:20 and well yea

7 0

2 years ago