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3 years ago

You don’t have ti explain just tell me if it’s true or not

Mathematics

2 answers:

Marysya12 [62]3 years ago

8 0

The student is not correct ..

Misha Larkins [42]3 years ago

3 0

Answer:

no its not true

Step-by-step explanation:

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Use your knowledge about tire bebeling to fill out the following chert. Remember that I inch 254 mm

faltersainse [42]

Answer:

zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Step-by-step explanation:

5 0

3 years ago

Rocco runs diagonally across a square field.

valkas [14]

Rocco would have to run diagonally 27 times

7 0

3 years ago

What is the inequality of 5(3-x)-4(2-3x)>2

Aneli [31]

5(3 - x) - 4(2 - 3x) > 2

15 - 5x - 8 + 12x > 2 distributed 5 and 4 on the left side

7 + 7x > 2 added like terms (15 and -8) and (-5x and 12x)

-7 -7

7x > -5

$\frac{7x}{7} > \frac{-5}{7}$

$x > \frac{-5}{7}$

3 0

4 years ago

What is the measure of ∠b?°

riadik2000 [5.3K]

<b = 180 -45

<b = 135

answer

<b = 135 degrees

7 0

4 years ago

Evaluate without using a calculator (x2y-3)0+x1/3-(4x)1/2 when x = 64 and y = 27. Show work.

aleksley [76]

Given:

The expression is:

$(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}$

To find:

The value of the given expression when $x=64$ and $y=27$ .

Solution:

We have,

$(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}$

Putting $x=64$ and $y=27$ , we get

$=((64)^2(27)-3)^0+(64)^{\frac{1}{3}}-(4(64))^{\frac{1}{2}}$

It can be written as

$=((64)^2(27)-3)^0+(4^3)^{\frac{1}{3}}-(4)^{\frac{1}{2}}(64)^{\frac{1}{2}}$

$=1+4-2(8)$ $[\because a^0=1,a\neq 0]$

$=5-16$

$=-11$

Therefore, the value of the given expression $-11$ when $x=64$ and $y=27$ .

4 0

3 years ago