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bogdanovich [222]
2 years ago
15

Marco leaves the bathroom faucet running for 22 minutes while he gets ready in the morning. running the faucet for 5 minutes was

tes the same amount of energy as leaving a 60-watt light bulb on for 14 hours. how much energy did marco waste, in terms of hours which a 60-watt light bulb would remain on? a. 7.9 hours b. 61.6 hours c. 56.0 hours d. 264.0 hours
Mathematics
1 answer:
lord [1]2 years ago
5 0

The amount of energy waste, in terms of hours which a 60-watt light bulb would remain on, is 61.6 hours then the correct option is B.

<h3>What are ratio and proportion?</h3>

A ratio is an ordered couple of numbers a and b, written as a/b where b can not equal 0. A proportion is an equation in which two ratios are set equal to each other.

Marco leaves the bathroom faucet running for 22 minutes while he gets ready in the morning.

Running the faucet for 5 minutes wastes the same amount of energy as leaving a 60-watt light bulb on for 14 hours.

Then we have

\begin{aligned} \dfrac{5\ minutes}{14 \ hours } &=\dfrac{1\ minute }{x \ hours}\\\\x &= 2.8  \ hours \end{aligned}

So, the rate is 2.8 hours per minute.

Since macro leaves the bathroom faucet running for 22 minutes. Then the waste of energy is leaving a 60-watt light bulb will be

→22 minutes × 2.8 hours/minute = 61.6 hours.

More about the ratio and the proportion link is given below.

brainly.com/question/14335762

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I need to know what mathematical operation applies to Problem: Tricia manages the front office at a local doctor's office and ne
Mrrafil [7]
                  <span>      <span /><span><span>Week 1        Week 2
</span> <span> Monday               480             480
</span><span>Tuesday              450             480
</span> <span> Wednesday        495             480
</span> <span> Thursday             480             480
</span> <span> Friday                   300             480
</span> <span> Total (minutes) 2205           2400

Week 1: 2205 mins / 60 mins = 36.75 hours
Week 2: 2400 mins / 60 mins = 40 hours

Add up all the minutes in a week. 
Divide the sum by 60 minutes to get the total hours worked for the week. 
Both weeks, the front office clerk did not exceed the 40 hours maximum. 
There will be no overtime pay. </span></span></span>
4 0
3 years ago
PLEASE LOOK AT ATTACHMENT-25 POINTS
max2010maxim [7]

Answer:

Step-by-step explanation: 10/2 = 5

20^2= x^2 + 5^2

400=x^2+25

x^2=375

x= 19.4

3 0
3 years ago
Read 2 more answers
Find the trigonometric integral. (Use C for the constant of integration.)
Olin [163]

Suppose we let u=\sin\theta+\cos\theta, so that \mathrm du=(\cos\theta-\sin\theta)\,\mathrm d\theta.

Also, recall the double angle identity for cosine:

\cos(2\theta)=\cos^2\theta-\sin^2\theta=(\cos\theta-\sin\theta)(\cos\theta+\sin\theta)

So, we can rewrite and compute the integral using the substitution, as

\displaystyle\int\cos(2\theta)(\sin\theta+\cos\theta)^3\,\mathrm d\theta

=\displaystyle\int u\cdot u^3\,\mathrm du

=\displaystyle\int u^4\,\mathrm du

=\dfrac{u^5}5+C

=\boxed{\dfrac{(\cos\theta+\sin\theta)^5}5+C}

4 0
3 years ago
One of the interior angles of a triangle is equal to 30°, and one of the exterior angles is equal to 40°. Find the remaining int
irina1246 [14]

Answer:

The remaining interior angles of this triangle are 140º and 10º

Step-by-step explanation:

The sum of the interior angles of a triangle is always 180º.

A triangle has 3 angles. In this problem, we have one of them, that i am going to call A1 = 30º.

The sum of a interior angle with it's respective exterior angle is also always 180º.

We have that one of the exterior angles is equal to 40°. So it's respective interior angle is

40º + A2 = 180º

A2 = 180º - 40º

A2 = 140º

Now we have two interior angles, and we know that the sum of the 3 interior angles is 180º. So:

A1 + A2 + A3 = 180º

A3 = 180º - A1 - A2

A3 = 180º - 30º - 140º

A3 = 180º - 170º

A3 = 10º

7 0
3 years ago
The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the
liberstina [14]

Answer:

<u>188 children</u> and <u>145 adults</u> were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

<u><em>Let the number of children admitted be </em></u>x.<u><em /></u>

<u><em>And the the number of adults admitted be </em></u>y.<u><em /></u>

So, the total people enter the park:

x+y=333\\\\x=333-y\ \ \ ...(1)

Thus, the total amount collected of the admission fee:

1.50(x)+4(y)=862\\\\

Substituting the value of x from equation (1):

1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.

<u><em>Thus, the number of adults = 145.</em></u>

Now, to get the number of children by substituting the value of y in equation (1) we get:

x=333-y\\\\x=333-145\\\\x=188.

<u><em>Hence, the number of children = 188.</em></u>

Therefore, 188 children and 145 adults were admitted in the park.

4 0
4 years ago
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