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vesna_86 [32]
2 years ago
9

If Janelle originally started 575

Mathematics
1 answer:
Ierofanga [76]2 years ago
3 0

Given that Janelle travels at 65 mph. the number of more hours it will

take her to reach her destination is approximately 5 hours.

<h3>How can the time to reach her destination be calculated?</h3>

Possible part of the question that appear missing are;

The distance Janelle drove in 4 hours = 260 miles

The distance from which she started = 575 miles

Required:

The number of extra hours it will take her to reach her destination

Solution:

The remaining distance = 575 miles - 260 miles = 315 miles

Speed =  \mathbf{ \dfrac{Distance}{Time}}

Janelle's \ average \ speed = \dfrac{260 \, miles }{4 \, hours} = \mathbf{ 65 \, mph}

Time = \dfrac{Distance}{Speed}

Which gives;

Time \ to \ reach \ her \ destination = \dfrac{315 \, miles}{65 \, mph} = 4\frac{11}{13} \, hours \approx \mathbf{ 5 \, hours}

The time it takes Janelle to reach her destination ≈<u> 5 hours</u>

Learn more about average speed during motion here:

brainly.com/question/11241290

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Solve x4 – 17x2 + 16 = 0.<br> Let u =<br> Select all of the zeroes of the function. i i
Soloha48 [4]

Solve \ x^4 - 17x^2 + 16 = 0

To solve this equation , we need to write it in quadratic form

ax^2+bx+c=0

To get the equation in quadratic form we replace x^2 with u

x^2 = u

x^4 - 17x^2 + 16 = 0 can be written as

(x^2)^2 - 17x^2 + 16 = 0, Replace u for x^2

So equation becomes

u^2 - 17u + 16 = 0

Now we factor the left hand side

-16  and -1  are the two factors whose product is +16  and sum is -17

(u-16) (u-1) = 0

u -16 = 0  so u=16

u-1 =0  so u=1

WE assume u = x^2, Now we replace u with x^2

u = 16 so \ it \ becomes \ x^2 =16

Now take square root on both sides , x= +4  and x=-4

u = 1 so \ it \ becomes \ x^2 =1

Now take square root on both sides , x= +1  and x=-1

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8 0
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At what corridnate point do y= 1/2 x + 4 and x + 4y = 4 intersect.
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(-4;2)

Step-by-step explanation:

1. if y=1/2 x+4, then 2y=x+8; it is possible to re-write as x-2y+8=0;

2. if x+4y=4, it is possible to re-write it as x+4y-4=0;

3. if x-2y+8=0 and x+4y-4=0, then x-2y+8=x+4y-4; ⇒ -2y+8=4y-4; ⇒ 6y=12; ⇔ y=2.

4. if y=2, then it is possible to substitute its value into any equation given in the condition:

x+4y=4 (substitution y=2); ⇒ x+8=4; ⇒ x= -4.

5. finally x= -4; y=2. It means (-4;2)

PS. the suggested solution is not the only way to resolve this task.

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