1 + 109
2 + 108
3 + 107
4 + 106
(...)
106 + 4
107 + 3
108 + 2
109 + 1
There are 109 such pairs - unless you don't want to count the combinations of the same numbers but in different order (e.g. 50 + 60 and 60 + 50) - then there are 55 such pairs (up to 55 + 55).
You can also count 0 - sometimes we treat it as a whole number, sometimes we don't - then add two pairs (0 + 110 and 110 + 0) to the 109 pairs result, or 1 pair for 55 pairs result.
I hope it's quite understandable :)
Answer: ok well if you know that 2(x+3) + 4 = 4x + 6
ok well you know that 4+3+2= 9, and 4+ 6= 10 then that means that x must be 1 so they equal.
Step-by-step explanation:
Umm I kind of explained it already but hope this helps!
The HL Postulate
You know that the two hypotenuses are congruent and that the two triangles each contain a shared segment in the middle (so by the reflexive property they are congruent). You have two congruent hypotenuses and two congruent legs, so you can conclude congruency by HL.
If you found this helpful, please make this the brainliest answer! :)
ANSWER: B 7/22
I hope this helped
Answer:
Step-by-step explanation:
Draw the second altitude MB (see attached diagram).
Quadrilateral HLMB is a rectangle, then LM = HB = 3 units.
Trapezoid KLMN is isosceles trapezoid (because KL=MN), thus
Triangle LHN is right triangle, then by Pythagorean theorem,
Consider right triangle KLH. In this triangle,
So,
