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lbvjy [14]
3 years ago
5

Help me please 50 points and brainliest.

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

The answer is -2

Sure hope this helps you

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Victoria is interested in opening her own candy store. She has researched and found that of the 14 stores she investigated, the
Anna71 [15]

Answer:

99% confidence interval for the average start up cost is [76.575 , 123.425].

Step-by-step explanation:

We are given that of the 14 stores Victoria investigated, the average start up cost is 100 thousand dollars with a standard deviation of 29.1 thousand dollars.

So, the pivotal quantity for 99% confidence interval for the population average start up cost is given by;

           P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample average start up cost = 100 thousand dollars

             \sigma = sample standard deviation = 29.1 thousand dollars

             n = sample of stores = 14

             \mu = population average start up cost

<em>So, 99% confidence interval for the average start up cost, </em>\mu<em> is ;</em>

P(-3.012 < t_1_3 < 3.012) = 0.99

P(-3.012 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 3.012) = 0.99

P( -3.012 \times {\frac{s}{\sqrt{n} } < {\bar X - \mu} < 3.012 \times {\frac{s}{\sqrt{n} } ) = 0.99

P( \bar X-3.012 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +3.012 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-3.012 \times {\frac{s}{\sqrt{n} } , \bar X +3.012 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 100-3.012 \times {\frac{29.1}{\sqrt{14} } , 100+3.012 \times {\frac{29.1}{\sqrt{14} } ]

                                                 = [76.575 , 123.425]

Therefore, 99% confidence interval for the population average start up cost for a candy store is [76.575 , 123.425].

8 0
3 years ago
Helpppppppppppp plzzzzzzzzzzzzzzzzzzz
ZanzabumX [31]

Answer:

Step-by-step explanation:

\left[\begin{array}{ccc}7&31\\142&19\end{array}\right] = 7(19) - 142(31) = <em>- 4269</em>

\left[\begin{array}{ccc}7&11&21\\55&-8&2\\-16&-1&-9\end{array}\right] = 7(- 8)(- 9) + 11(2)(- 16) + 21(55)(- 1) - 21(- 8)(- 16) - 7(2)(- 1) - 11(55)(- 9) = <em>1768</em>

\left[\begin{array}{ccc}9.07&6.02&2.01\\-30.7&2.5&3.5\\3.55&-1.1&2.35\end{array}\right] = 9.07(2.5)(2.35) + 6.02(3.5)(3.55) + 2.01(- 30.7)(- 1.1) - 2.01(2.5)(3.55) - 9.07(3.5)(- 1.1) - 6.02(- 30.7)(2.35) = <em>647.3561</em>

4 0
3 years ago
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