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lbvjy [14]
2 years ago
5

Help me please 50 points and brainliest.

Mathematics
1 answer:
Sonja [21]2 years ago
3 0

The answer is -2

Sure hope this helps you

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How many pairs of whole numbers have a sum of 110
katovenus [111]
1 + 109
2 + 108
3 + 107
4 + 106
(...)
106 + 4
107 + 3
108 + 2
109 + 1

There are 109 such pairs - unless you don't want to count the combinations of the same numbers but in different order (e.g. 50 + 60 and 60 + 50) - then there are 55 such pairs (up to 55 + 55).

You can also count 0 - sometimes we treat it as a whole number, sometimes we don't - then add two pairs (0 + 110 and 110 + 0) to the 109 pairs result, or 1 pair for 55 pairs result.

I hope it's quite understandable :)
8 0
4 years ago
I need some help with 2 step equations. Like this one 2(x+3) + 4 =4x + 6
Vladimir [108]

Answer: ok well if you know that 2(x+3) + 4 = 4x + 6

ok well you know that 4+3+2= 9, and 4+ 6= 10 then that means that x must be 1 so they equal.

Step-by-step explanation:

Umm I kind of explained it already but hope this helps!

5 0
3 years ago
Read 2 more answers
What postulate can be used to prove the triangles are congruent?
Komok [63]
The HL Postulate

You know that the two hypotenuses are congruent and that the two triangles each contain a shared segment in the middle (so by the reflexive property they are congruent). You have two congruent hypotenuses and two congruent legs, so you can conclude congruency by HL.

If you found this helpful, please make this the brainliest answer! :)


3 0
3 years ago
Which expression best represents the value of pi?
Hoochie [10]
ANSWER: B 7/22
I hope this helped
5 0
3 years ago
Read 2 more answers
PLS HELP ME!!!!!!!! 99 POINTS
Amiraneli [1.4K]

Answer:

\angle LKN=\arctan1.8\sqrt{97}\approx 86.77^{\circ}

Step-by-step explanation:

Draw the second altitude MB (see attached diagram).

Quadrilateral HLMB is a rectangle, then LM = HB = 3 units.

Trapezoid KLMN is isosceles trapezoid (because KL=MN), thus

KH = BN = \dfrac{KN-HB}{2}=\dfrac{13-3}{2}=5\ units\\ \\HN=HB+BN=3+5=8\ units

Triangle LHN is right triangle, then by Pythagorean theorem,

LN^2=LH^2+HN^2\\ \\89^2=LH^2+8^2\\ \\LH^2=89^2-8^2\\ \\LH^2=(89-8)(89+8)\\ \\LH^2=81\cdot 97\\ \\LH=9\sqrt{97}\ units

Consider right triangle KLH. In this triangle,

\tan\angle LKH=\{\tan\angle LKH\}=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{LH}{KH}=\dfrac{9\sqrt{97}}{5}=1.8\sqrt{97}\ units

So,

\angle LKN=\arctan1.8\sqrt{97}\approx 86.77^{\circ}

5 0
3 years ago
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