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Volgvan
3 years ago
13

What is the value of 7p7 a)1 b)14 c)49 d)5040

Mathematics
1 answer:
STatiana [176]3 years ago
8 0
D. 5040
7p7=7
so you do 7*6*5*4*3*2*1= 5040
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What is the solution of (x-9)^2/3=25 algebraicallt
AnnyKZ [126]

\bf \cfrac{(x-9)^2}{3}=25\implies (x-9)^2=75\implies \sqrt{(x-9)^2}=\sqrt{75}\implies x-9=\pm\sqrt{75} \\\\\\ x=\pm \sqrt{75}+9\implies x\approx \begin{cases} 17.66\\ -0.34 \end{cases}

7 0
3 years ago
In ∆MNP, m∠N = 90º, NH – altitude, m∠P = 21º, PM = 4 cm. Find MH.
Sveta_85 [38]

Answer:

0.51 cm

Step-by-step explanation:

In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°

By the sine definition,

\sin \angle P=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{MN}{MP}\\ \\MN=MP\sin \angle P\\ \\MN=4\sin 21^{\circ}\approx 1.43\ cm

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

\cos \angle M=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{MH}{MN}\\ \\MH=MN\cos \angle M

In the right triangle, two acute angles are always complementary, so

m\angle M=90^{\circ}-m\angle P=90^{\circ}-21^{\circ}=69^{\circ}

Thus,

MH=1.43\cos 69^{\circ}\approx 0.51\ cm

7 0
3 years ago
How do you solve this
AlladinOne [14]

Answer:

  • domain: all terms are defined for <em>all real numbers</em>
  • solution: x = 6

Step-by-step explanation:

Rewrite the equation as a single exponential. After taking the log, the solution becomes obvious.

5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6

6 0
3 years ago
HELP ASAP FOR BRAINLIEST!!
Diano4ka-milaya [45]

Answer:

Not equivalent

Step-by-step explanation:

The three would also be distributed to z making the correct equivalent expression 15+3z

8 0
3 years ago
Need help. please give me a legit answer.
LekaFEV [45]
Theyre all labeled correctly, what exactly is the question?
5 0
3 years ago
Read 2 more answers
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