Answer:
x = 2.3202
Step-by-step explanation:
Given equation:
on taking log both sides, we get
now,
using the property of log function
log(aᵇ) = b × log(a)
therefore,
we get
(3x-5)log(10) = xlog(7)
now,
log(10) = 1
and
log(7) = 0.84509
thus,
( 3x - 5 ) × 1 = 0.84509x
or
3x - 0.84509x - 5 = 0
or
2.15491x = 5
or
x = 2.3202
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Check the picture below.
make sure your calculator is in Degree mode.
F(19)= (3/(19+2)) - sqrt(19-3)
= (3/21) - sqrt(16)
= (1/7) - 4
= (1/7) - (28/7)
= -27/7
= - 3 6/7
Answer:
Step-by-step explanation:
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