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3 years ago

Calculate the value of 2a + 3b if a = -1 and b = 2

Mathematics

1 answer:

romanna [79]3 years ago

3 0

Plug in the numbers to the variables and you get 4 as ur answer

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How many times does 7 go in to 37

Tcecarenko [31]

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3 years ago

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What is the quotient (x^3-3x^2+3x-2) ÷ (x^2-x+1)

qaws [65]

Answer:

x-2

Step-by-step explanation:

x3−3x2+3x−2/x2−x+1

(x−2)(x2−x+1)/x2−x+1

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3 years ago

Terri played 70 tournament chess games during the school year and won 49 of them. What is her win-to-loss ratio?

Scilla [17]

Alright so the answer would be letter B, because

win-to-loss

49 to 21 (You can determine her losses by subtracted the number of wins from her total number of games played)

Now you must simplify your answer

7 is the greatest common factor (GCF) of both 49 and 21

Now divide both 49 and 21 by 7 to get

7 to 3

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3 years ago

18 divided by 20 equals

balandron [24]

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3 years ago

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A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014$

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

7 0

3 years ago