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densk [106]
2 years ago
15

Solve the following equations:a) (x-3)(-2x+1)= 0.b) (x+7)(2-4x)=0.​

Mathematics
1 answer:
seraphim [82]2 years ago
4 0

Answer:

hope it's help you sorry for dirty handwriting

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Mr. Lester's maximum heart rate is 180 beats per minute. When he exercises at the gym.
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2 years ago
Write the equation of the line shown in point-slope form. (2,1) (3,8)
Ulleksa [173]

<u>Answer:</u>

The line equation that passes through the given points is 7x – y = 13

<u>Explanation:</u>

Given:

Two points are A(2, 1) and B(3, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) in point slope form is given by

\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}

{(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1)..........(1)

here, in our problem x1 = 3, y1 = 8, x2 = 2 and y2 = 1.

Now substitute the values in (1)

(y-8) = \frac{(1 - 8)}{(2 - 3)}\times(x- 3)

(y -8) = \frac{(- 7)}{(-1)}(x-3)

y – 8 = 7(x – 3)

y – 8 = 7x – 21  

7x – y = 21 – 8  

7x – y = 13  

Hence, the line equation that passes through the given points is 7x – y = 13

3 0
3 years ago
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