Ask question

Ask question

All categories

3 years ago

5

What is the mathematical representation of joules law of heating ?

1 answer:

Elza [17]3 years ago

5 0

Answer:

Q = I^2 R T

Step-by-step explanation:

What is the mathematical representation of joules law of heating

What is joules law of heating ??

Joule’s law is a mathematical description of the rate at which resistance in a circuit converts electric energy into heat energy.

Mathematically

Q = I^2 R T

Where,

Q indicates the amount of heat

I show electric current

R is the amount of electric resistance in the conductor

T denotes time

You might be interested in

Teaser has 38 point she divides the coins equally among her self and her three brothers how many coins does each person get are

Serhud [2]

Answer:

Each person including Teaser will get 9.5 coins.

Step-by-step explanation:

Teaser has 38 points

There is

-Brother 1

-Brother 2

-Brother 3

-Teaser

38 divided by 4

= 9.5

Therefor each will get 9 1/2 coins.

Please leave a good rating if this helped :)

-Adam

7 0

3 years ago

Avani wrote the linear equation y = 5 x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5 x + 4 and t

Margarita [4]

Avani wrote the linear equation y = 5x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5x+ 4 and that passes through (15,–2). If her new equation is in the form $y-\frac{1}{5}x+b$ , what is the value of b?

$\bf y=mx+b$

m is the slope
b is the y-intercept

The equation of a line that is perpendicular to another line always has the opposite reciprocal slope. In the original equation, the slope is 5. The opposite of 5, which refers to the sign, is -5. The reciprocal of -5 is -1/5. That means the slope of the new line is -1/5.

The perpendicular line:

Has a slope of $-\frac{1}{5}$

Passes through the point (15, -2)

To find the equation of a line that passes through a specific point, you need to use slope-intercept form.

$\bf y-y_{1} =m(x-x_{1})$

y₁ is the y-value of the point
m is the slope
x₁ is the x-value of the point

y₁ is -2, m is -1/5, and x₁ is 15.

Substitute the known values into the equation:

$y-(-2)=-\frac{1}{5}(x-15) \rightarrow y+2= -\frac{1}{5}(x-15)$

Open the parentheses and distribute:

$-\frac{1}{5}(x-15) \rightarrow -\frac{1}{5} \cdot x\ + -\frac{1}{5} \cdot -15 \rightarrow -\frac{1}{5}x +3$

The new equation will be:

$y+2=-\frac{1}{5}x+3$

Lastly, you need to move the positive 2 to the other side to keep it in y = mx + b form.

$y+2-2=-\frac{1}{5}x+3-2 \rightarrow y=-\frac{1}{5}x+1$

The equation of the perpendicular line is:

$\bf y=-\frac{1}{5}x+1$

The value of b is 1.

5 0

3 years ago

Which expression is equivalent to 3x/5

emmasim [6.3K]

6x/10
12x/20
24x/40
48x/80

7 0

3 years ago

Read 2 more answers

Help pls. What is the factor of: 12p^2 + 20p - 8

garik1379 [7]

I got 3 when i put it into the calculator but you can check behind me

6 0

3 years ago

Read 2 more answers

The initial point of a⃗ is (−2,4), and its terminal point is (−5,−2). What is the value of ‖a⃗ ‖? Give your answer as a simplifi

lyudmila [28]

Answer:

$3\sqrt{5}.$

Step-by-step explanation:

It is given that the initial point of $\vec{a}$ is (-2,4) and terminal point is (-5,-2). So, $\vec{a}$ is defined as

$\vec{a}=(-5-(-2))\hat{i}+(-2-4)\hat{j}$

$\vec{a}=(-5+2)\hat{i}+(-2-4)\hat{j}$

$\vec{a}=-3\hat{i}-6\hat{j}$

The magnitude of $\vec{v}=a\hat{i}+b\hat{j}$ is

$|\vec{v}|=\sqrt{a^2+b^2}$

The magnitude of $\vec{a}$ is

$|\vec{a}|=\sqrt{(-3)^2+(-6)^2}$

$|\vec{a}|=\sqrt{9+36}$

$|\vec{a}|=\sqrt{45}$

$|\vec{a}|=3\sqrt{5}$

Modulus of magnitude is

$||\vec{a}||=|3\sqrt{5}|=3\sqrt{5}$

So, the magnitude of $\vec{a}$ is $3\sqrt{5}.$

8 0

3 years ago