Answer:
y = 2(x-3)^2 -12
y = -4/9(x-2)^2 +7 bonus
Step-by-step explanation:
The vertex form of a parabola is
y = a(x-h)^2 + k where (h,k) is the vertex
y = a(x-3)^2 - 12
We have one point given (0,6)
6 = a (0-3) ^2 -12
6 = a (-3)^2 -12
6 = 9a-12
Add 12 to each side
6+12 = 9a
18 = 9a
Divide each side by 9
18/9 = 9a/9
a=2
y = 2(x-3)^2 -12
We follow the same steps for the bonus
y = a(x-2)^2 +7
Substitute the point into the equation
3 = a (-1-2)^2 +7
3 =a (-3)^2 +7
3 = 9a +7
subtract 7 from each side
3-7 = 9a +7-7
-4 = 9a
Divide by 9
-4/9 =a
y = -4/9(x-2)^2 +7
First answer: 160
Second answer: 300
An equilateral polygon has congruent sides, like a rhombus.
An equiangular polygon has congruent interior angles, like a rectangle.
In other words: Equilateral doesn't necessarily have congruent INTERIOR angles while equiangular does have/need congruent interior angles.
Answer:
x = 20
y = 10
m∡8 = 110°
Step-by-step explanation:
m∡1 + m∡2 = 180
5x + y + 3x + y = 180
8x + 2y = 180
m∡1 = m∡8 (they are alternate-exterior angles and are congruent)
5x + y = 3x + 5y
2x = 4y
x = 2y
Substitute '2y' for 'x' in 8x + 2y = 180
8(2y) + 2y = 180
18y = 180
y = 10
x = 2(10)
x = 20
m∡8 = 3(20) + 5(10) = 110°
Answer:
3/18
Step-by-step explanation:
