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3 years ago

Which are vertical angles?

Mathematics

2 answers:

Oksanka [162]3 years ago

4 0

Hello.

Vertical angles are two sets of angles congruent to each other, both on opposite sides, but measure the same.

In the diagram shown, both angles ∠BFC and ∠EFA are identical, it seems mirrored, thus they are vertical angles.

The correct answer is B.

guapka [62]3 years ago

3 0

Step-by-step explanation:

AFE-BFD<---------------

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Factor x^2 + 25 in the complex numbers

zzz [600]

This expression cannot be factored with rational numbers. The polynomial is not factorable with rational numbers.

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4 years ago

Evaluate [7 - (2 - 5(4 - 2) + 7)] + 2

motikmotik

You are correct. here it is step by step.

[7-(2-5(2)+7)] +2
[7-(2-10+7)]+2
[7-(-1)]+2
8+2
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3 years ago

Read 2 more answers

_ 1. If U = {1,2,3,4,5) and A= {2,4} then A' should be?

kirza4 [7]

If U={1,2,3,4,5) and A={2,4) then A' should be

Ans» d.{1,3,5}

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3 years ago

I need help with dis. well both

timurjin [86]

Answer:first one is 38.67 and the second one is 12

Step-by-step explanation:

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4 years ago

Read 2 more answers

A school director must randomly select 6 teachers to part in a training session. There are 34 teachers at school. In how many di

prohojiy [21]

Answer:

Total possible ways to select 6 teachers from 34 teacher are $^{34}C_6=1344904$ .

Step-by-step explanation:

It is given that total number of teachers at a school is 34.

The school director must randomly select 6 teachers to part in a training session.

$^nC_r=\frac{n!}{r!(n-r)!}$

Where, n is total possible outcomes and r is number of selected outcomes.

Total teachers = 34

Selected teachers =6

Total number of possible ways to select 6 teachers from 34 teacher is

$^{34}C_6=\frac{34!}{6!(34-6)!}$

$^{34}C_6=\frac{34\times 33\times 32\times 31\times 29\times 28!}{6!(28)!}$

$^{34}C_6=1344904$

Therefore total possible ways to select 6 teachers from 34 teacher are $^{34}C_6=1344904$ .

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3 years ago