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scoundrel [369]
2 years ago
14

A tax preparation firm is interested in comparing the quality of work at two of its regional offices. the observed frequencies s

howing the number of sampled returns with errors and the number of sampled returns that were correct are as follows.
regional office
return office 1 office 2
error 35 28
correct 217 274
Mathematics
1 answer:
Veronika [31]2 years ago
7 0

The sample proportion of returns with errors at the two tax offices will be 0.1389 and 0.0927 respectively.

<h3>How to calculate the sample proportion?</h3>

From the information, the the observed frequencies showing the number of sampled returns with errors and the number of sampled returns were given.

The sample proportion will be:

P1 = 35/(35 + 217)

= 35/252

= 0.1389

P2 = 28/(28 + 274)

= 28/302

= 0.0927

Learn more about sample proportion on:

brainly.com/question/24232216

#SPJ1

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The area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = \frac{1}{2}\times \pi r^2

                                      $=\frac{1}{2}\times \pi\times 4^2

                                      $=\frac{1}{2}\times \pi\times 16

Area of the semi-circle = $8\pi cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

AC^2+BC^2=AB^2

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AC^2=48

AC=4\sqrt{3} cm

Base of the triangle ABC = 4\sqrt{3} cm

Height of the triangle = 4 cm

Area of the triangle ABC = \frac{1}{2}\times b \times h

                                          $=\frac{1}{2}\times 4\sqrt{3}  \times 4

Area of the triangle ABC =  8\sqrt{3} cm²

Area of the shaded region

                   = Area of the semi-circle – Area of the triangle ABC

                   = $8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2

                   = $8(\pi \ -\sqrt{3})\ \text{cm}^2

Hence the area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

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