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3 years ago

6

has 4 glass ornaments: blue, orange, pink, and purple. How many ways can she hang them in a row so that the blue and pink orname

nts are NOT next to each other?

2 answers:

Tatiana [17]3 years ago

7 0

There are 3 different ways she can hang them

Natali [406]3 years ago

6 0

There is 3 ways can i have brainliest answer if i am right

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R-18=27 Solve this equation

Flauer [41]

Step-by-step explanation:

r - 18 = 27

r = 27 + 18

r = 45

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X=<br> Length=<br> Width=<br> WILL GIVE BRAINLIEST + 5 star

babymother [125]

Answer:

x = 20

Length = 20ft

Width = 12ft

Step-by-step explanation:

A = 240

x^2 - 8x = 240

x^2 - 8x - 240 = 0

x^2 - 20x + 12x - 240 = 0

x(x-20) + 12(x-20) = 0

(x+12)(x-20) = 0

x = 20

x = -12 (which we discard since x is a length)

So the dimensions are 20ft and 20-8 = 12ft

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3 years ago

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Answer:

slope= -7

Step-by-step explanation:

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3 years ago

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How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .

Therefore, the mixture would contain $(210 + 0.15\, x) \; \rm lb$ of copper.

The mass of that mixture would be $(700 + x)\; \rm lb$ . The mass fraction of copper in that mixture would be:

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%$ .

This ratio is supposed to be equal to $25.5\%$ . These two pieces of equations combine to give an equation about $x$ :

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%$ .

$\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255$ .

Simplify and solve for $x$ :

$210 + 0.15\, x= 0.255\, (700 + x)$ .

$(0.255 - 0.15)\, x= 210 - 0.255 \times 700$ .

$\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300$ .

Therefore, $300\; \rm lb$ of that $15\%$ alloy would be required.

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2 years ago

Convert 1 radian to degrees. Round your answer to the nearest degree.

svetoff [14.1K]

Radian is pure measure based on the radius of the circle.
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