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Oksi-84 [34.3K]
2 years ago
12

An instrument maker creates a triangle in the shape of an isosceles triangle by bending a metal rod. the rod is 13 inches long,

and the bottom of the triangle is longer than the two sides. what is the length of the longest side?
the length of the longest slide is inches. the other two sides will each be
inches in length.
Mathematics
1 answer:
Gre4nikov [31]2 years ago
8 0

The length of the longest slide is 5 inches. he other two sides will be 4  inches in length.

<h3>Length of the longest slide</h3>

Isosceles triangle

Given:

Total length=13 inches

Hence:

AC=BC<AB

Let AC=BC=x-1 inches

AB=x inches

Thus:

x-1+(x-1)+x=13

3x-2=13

3x=13+2

3x=15

divide both side by 3x

x=15/3

x=5 inches

Hence:

Other two side

x-1=5-1=4 inches

Therefore the length of the longest slide is 5 inches. he other two sides will be 4  inches in length.

Learn more about Length of the longest slide here:brainly.com/question/7807143

#SPJ1

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Yanka [14]

Since none of the options make sense with 23, I assume it was a typo, and you meant 2/3.

Let l,w and h be the length, width and height of the original prism, and l',w' and h' be the length, width and height of the new prism. We are given

l' = l\times \cfrac{2}{3},\quad w' = w\times \cfrac{2}{3},\quad h' = h\times \cfrac{2}{3}

Also, if we call V the original volume, and V' the volume of the new prism, we have

V = lhw,\quad V'=l'h'w'

Substitute the expressions for l', h' and w' in the formula for V':

V'=l'h'w' = l\times \cfrac{2}{3}\times w\times \cfrac{2}{3}\times h\times \cfrac{2}{3} = l\times h \times w \times \cfrac{2}{3}\times\cfrac{2}{3}\times\cfrac{2}{3} = V \times \left(\cfrac{2}{3}\right)^3 = V\times\cfrac{8}{27}

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3 years ago
What is the cube root of 512m^12n^15
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The perimeter of the scalene triangle is 88 cm.Which equation can be used to find the value of b if side a measures 12.5 cm?
Mariulka [41]

Answer:

A scalene triangle is one whose sides are all a different length. So there is no way you can find the length of b when you are only given the length of a and the perimeter.

Step-by-step explanation:

hopes it help :)

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3 years ago
Simplify (10-10i)/(-5i)
Phoenix [80]

Answer:

<h2>2 + 2i</h2>

Step-by-step explanation:

i-\text{imaginary\ unit}\\\\i=\sqrt{-1}\to i^2=-1\\\\=====================

\dfrac{10-10i}{-5i}=\dfrac{10}{-5i}+\dfrac{-10i}{-5i}=\dfrac{(10)(i)}{(-5i)(i)}+2=\dfrac{10i}{(-5)(i^2)}+2\\\\=\dfrac{10i}{(-5)(-1)}+2=\dfrac{10i}{5}+1=2i+2=2+2i

4 0
3 years ago
Prove that the inequality (a+1)·(a+1)&gt;(a−1)·(a−1) is not true for some values of a.
Effectus [21]

Explanation:

Consider the case a = -1. Then the expression becomes ...

  (-1+1)(-1+1) > (-1-1)(-1-1) . . . . test case

  0·0 > (-2)(-2) . . . . . simplified a bit

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If we subtract the right side from both sides, the inequality becomes ...

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  4a > 0

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The inequality is only true for positive values of "a". For a ≤ 0, the inequality will not be true.

7 0
4 years ago
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