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Rzqust [24]
3 years ago
12

A rectangle container that has a length of 30 cm,a width of 20 cm,and a height of 24 cm is filled with water to a depth of 15 cm

.When an additional 6.5 liters of water poured into the container,some water overflows.How many liters of water overflow the container?Use words, pictures,and numbers to explain your answer. (Remember 1 cm powers of 3 = 1 mL

Mathematics
2 answers:
Ket [755]3 years ago
7 0
<span>V(h 24) = 30 cm*20 cm*24 cm = 14400 cm³ =  14,4 liters</span>
<span>V(h 15) = 30 cm*20 cm*15 cm =    9000 cm³  =  9 liters</span>
<span>                         + 6,5 liters = + 6500 cm³      </span>
9 liters +   6,5 liters = 15,5 liters         =>   15,5 liters -14,4 liters = 1,1 liters
now  15500 cm³   =>    1100 cm³ =1,1 liters  too much !!
Answer:  1,1 liters of water overflow the container.<span>
</span>
serious [3.7K]3 years ago
5 0

<h3>Volume of overflow water = 1.1 Liters</h3>

<h3>Further explanation</h3>

The formula for finding the volume of prisms that must be recalled is:

<h3>Volume = Base Area × Height</h3>

Let us tackle the problem!

<u>Given:</u>

Length of Container = L = 30 cm = 3 dm

Width of Container = W = 20 cm = 2 dm

Height of Container = H = 24 cm = 2.4 dm

Depth of Water = D = 15 cm = 1.5 dm

Additional Volume of Water = 6.5 liters

<u>Unknown:</u>

Volume of Overflow Water = ?

<u>Solution:</u>

<em>Initial volume of water in container</em>

\texttt{Initial Volume of Water} = L \times W \times D

\texttt{Initial Volume of Water} = 3 \times 2 \times 1.5

\texttt{Initial Volume of Water} = 9 ~ \texttt{Liters}

<em>Final volume of water in container</em>

\texttt{Final Volume of Water} = \texttt{Initial Volume of Water} + \texttt{Additional Volume of Water}

\texttt{Final Volume of Water} = 9 + 6.5

\texttt{Final Volume of Water} = 15.5 ~ \texttt{Liters}

<em>Capacity of container</em>

\texttt{Volume of Container} = L \times W \times H

\texttt{Volume of Container} = 3 \times 2 \times 2.4

\texttt{Volume of Container} = 14.4 ~ \texttt{Liters}

<em>Volume of overflow water</em>

\texttt{Volume of overflow water} = \texttt{Final Volume of Water} - \texttt{Volume of Container}

\texttt{Volume of overflow water} = 15.5 - 14.4

\texttt{Volume of overflow water} = \boxed {1.1 ~ \texttt{Liters}}

<h3>Learn more</h3>
  • Volume of Horizontal Cylinder : brainly.com/question/5747433
  • Length of Cubical Steel Tank : brainly.com/question/4799206
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Volume of 3D Shapes

Keywords: Temperature , Density , Iron , Sphere , Volume , Mass , Rectangle , Container , Water , Overflow

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