Answer:
2/7
then 2/14
Step-by-step explanation:
Let P(H)=p be the probability of one head. In many scenarios, this probability is assumed to be p=12 for an unbiased coin. In this instance, P(H)=3P(T) so that p=3(1−p)⟹4p=3 or p=34.
You are interested in the event that out of three coin tosses, at least 2 of them are Heads, or equivalently, at most one of them is tails. So you are interested in finding the likelihood of zero tails, or one tails.
The probability of zero tails would be the case where you only received heads. Since each coin toss is independent, you can multiply these three tosses together: P(H)P(H)P(H)=p3 or in your case, (34)3=2764.
Now we must consider the case where one of your coin flips is a tails. Since you have three flips, you have three independent opportunities for tails. The likelihood of two heads and one tails is 3(p2)(1−p). The reason for the 3 coefficient is the fact that there are three possible events which include two heads and one tails: HHT,HTH,THH. In your case (where the coin is 3 times more likely to have heads): 3(34)2(14)=2764.
Adding those events together you get p3+3(p2)(1−p)=5464. Note that the 3 coefficient
Answer:
Step-by-step explanation:
f ( x 2 − 3 x + 2 ) = − x 2 + 3 x + 3
Answer:
First, we calculate for the volume of each can by using the equation,
V = πr²h
Substituting the known values,
V = π(1.5 in)²(6 in) = 42.39 in³ (that is if 3.14 is used in replacement of π)
Then, we multiply the volume by 36.
total volume = (42.39 in³)(36) = 1526.04 in³
Step-by-step explanation:
Answer:
24w⁹
Step-by-step explanation:
Hannah=h
raoul=r
h=6r
r+h=r+6r=7r=63
r=63/7=9
hannah=6*9=54minutes