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2 years ago

Veronica's health insurance deductible is $3,000. During the year, she has one

1 answer:

7 0

The maximum amount that she will pay during her hospital stay will be $3,000. Then the correct option is B.

<h3>What is deductible?</h3>

The amounts you pay out-of-pocket for covered health-care services prior to your insurance kicks in. For example, with a $2,000 deductible, you are responsible for the first $2,000 of approved treatments.

Veronica's health insurance deductible is $3,000.

During the year, she has one hospital stay, with charges totaling $10,700.

Then the maximum amount that she will pay during her hospital stay will be

You pay 20% of $100, or $20 if you've fulfilled your deductible. The rest is covered by the insurance company.

Then she has to pay only the deductible amount which is $3000.

More about the deductible link is given below.

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<h3>What is the use of medical records?</h3>

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2 years ago

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3 years ago

Read 2 more answers

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yulyashka [42]

We can see from Dr. Aguilera's findings that high levels of anxiety are associated with poor academic performance. However, the number of hours of sleep has little bearing on how well or poorly a student does in class.

The confounding variable is important to avoid obstacles to the measurement

<h3>How to illustrate the information?</h3>

Dr. Aguilera discovered a strong link between anxiety and academic achievement. Additionally, this number is negative, indicating a negative correlation between the two variables. According to this negative correlation, the value of the other variable decreases as the value of the first variable increases. Therefore, academic performance declines when anxiety levels rise.

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1 year ago

The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded

Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

$\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx$

Therefore;

$A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}$

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, $A_{1 shaded}$ = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

$A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526$

The shaded area, $A_{2 shaded}$ = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = $A_{1 shaded}$ + $A_{2 shaded}$

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

8 0

3 years ago