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egoroff_w [7]
2 years ago
13

A common motif in the poetry of this unit is death

SAT
1 answer:
Viefleur [7K]2 years ago
5 0

Various poets address the element of death in their poems by referring to it as something dark.

<h3>How poets address the element of death</h3>

Various poets address the element of death in their poems by mentioning something that relates to dark.

Death is used as a motif when it uses a symbol to represent death.

Thus, poets address the element of death in their poems by referring to it as something dark.

The complete question is below:

A common motif in the poetry of this unit is death. How do the various poets address the element of death?

Learn more about motif here: brainly.com/question/10751106

#SPJ1

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What does the word repurposing mean?
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Answer:

Repurposing is the use of something for a purpose other than its original intended use. Repurposing an item can be done by modifying it to fit a new use, or by using the item as is in a new way. The practice is not limited to physical items. It's common to repurpose marketing material and content.

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A single-price monopolist is a monopolist that sells each unit of its output for the same price to all its customers. Refer to E
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From the information provided, A single-price monopolist earns a total profit of $80 when it produces and sells 20 units of its good. See the attached for more information.

<h3>How do we arrive at $80?</h3>

Total profit  = revenue - cost

Revenue  = price x number of units sold

Revenue  at 20 units  =

20  x9 = $180

Given that Total cost at 20 units is $100, thus,
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6 0
2 years ago
A bat emits a sound at a frequency of 3. 00 × 104 hz as it approaches a wall. The bat detects beats such that the frequency of t
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Taking into account the Doppler efect, the speed of the bat is closest to 5.02 \frac{m}{s}.

The Doppler effect is defined as the apparent frequency change of a wave produced by the relative movement of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.

The following expression is considered the general case of the Doppler effect:

f1=f\frac{v+-vR}{v+-vE}

Where:

  1. f1, f: Frequency perceived by the receiver and frequency emitted by the issuer respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s⁻¹)
  2. v: Velocity of propagation of the wave in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 340 m/s
  3. vR, vE: Speed ​​of the receiver and the sender respectively. Its unit of measure in the S.I. is the m/s
  4. ±, ∓:
  • We will use the + sign:

In the numerator if the receiver approaches the sender

In the denominator if the sender moves away from the receiver

  • We will use the sign -:

In the numerator if the receiver moves away from the emitter

In the denominator if the sender approaches the receiver

In this case, a bat emits a sound at a frequency of 3.00×10⁴ Hz= 30,000 Hz as it approaches a wall.

The bat detects beats such that the frequency of the echo is 900 hz higher than the frequency the bat is emitting.

So, you know:

  • f1= 30,000 Hz + 900 Hz= 30,900 Hz
  • f= 30,000 Hz
  • v= 340 m/s
  • vE=vR= vbat
  • Receiver approaches the sender

Replacing in the expression is considered the general case of the Doppler effect:

30900 Hz=30000 Hz\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

Solving:

\frac{30900 Hz}{30000 Hz} =\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

1.03=\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

1.03×( 340\frac{m}{s} -vbat)= 340 \frac{m}{s} + vbat

1.03×340\frac{m}{s} - 1.03×vbat= 340 \frac{m}{s} + vbat

350.2\frac{m}{s} - 1.03×vbat= 340 \frac{m}{s} + vbat

350.2\frac{m}{s} - 340 \frac{m}{s}= vbat + 1.03×vbat

10.2 \frac{m}{s}= 2.03×vbat

10.2 \frac{m}{s}÷ 2.03 = vbat

<u><em>5.02 </em></u>\frac{m}{s}<u><em>= vbat</em></u>

In summary, the speed of the bat is closest to 5.02 \frac{m}{s}.

Learn more about the Doppler effect:

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