6 edges in a triangular pyramid
Answer:
y = 8
Step-by-step explanation:
for the triangles to be congruent, 2y + 20 must equal 36.
2y + 20 = 36
subtract 20 from each side of the equation:
2y = 16
divide both sides by 2:
y = 8
Jo's Mobile Plan:
- Fixed monthly charge = £16
- Monthly 150 free minutes, post that 13p (or £0.13) per minute,
- Monthly 150 free texts, post that 15p (or £0.15) per text
Jo's mobile phone usage details:
- 170 minutes of calls
- 182 texts
Total Charges for Jo = Fixed Monthly Charge + Charges for Calls + Charges for Texts
⇒ Total Charges for Jo = 16 + (170-150) × 0.13 + (182-150) × 0.15
⇒ Total Charges for Jo = 16 + (20) × 0.13 + (32) × 0.15
⇒ Total Charges for Jo = 16 + 2.6 + 4.8
⇒ Total Charges for Jo = 23.4
Hence, Jo should be charged £23.4 for the month.
Answer:
It's B
... because if you evaluate it it'll be 9x - 6xy, and 2xy + 2x^2
-6xy and 2xy are like terms
Answer:
81π for the x axis.
Step-by-step explanation:
STEP ONE: Determine the intersection.
we are given from the question that y = x^2 and y = 6x − x^2. Therefore if y = x^2, then we will have;
x^2 = 6x - x^2 ---------------------------------------------------------------------------------[1].
Solving and factorizing the equation [1] above give us x = 0 and x = 3 (that is x[6 -2x] = 0 ). Therefore, the point of intersection = (0,0) and (3,9).
<u>STEP TWO</u><em>: </em>Determine the value for the cross sectional area.
The cross sectional area= [6x - x^2]π - [x2]^2 π. --------------[2].
The cross sectional area = -12 π[x -3]x^2.
<u>STEP THREE:</u> integrate the cross sectional area taking x =3 and x =0 as the upper and lower integration limits or boundaries with respect to dx to determine the vome in the x axis.
<h3>volume =∫-12 π[x -3]x^2 dx.</h3><h3 /><h3>volume = -12 π[ (3)^4/4 - (3)^3 ] = 81π.</h3>
volume, v with respect to the x axis = 81π
