Answer:
95% of confidence intervals for the proportion of all dies that pass the probe.
(0.4867 , 0.6453)
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given sample size 'n' = 150
<em>The sample proportion </em>
Level of significance = 0.05
<em>The critical value Z₀.₀₅ = 1.96</em>
<u><em>Step(ii):</em></u>-
<em>95% of confidence intervals for the proportion of all dies that pass the probe.</em>
( 0.566 - 0.0793 , 0.566 + 0.0793)
(0.4867 , 0.6453)
<u><em>Conclusion</em></u>:-
<em>95% of confidence intervals for the proportion of all dies that pass the probe.</em>
<em>(0.4867 , 0.6453)</em>