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2 years ago

In the figure, ∆ABD ≅ ∆CBD by Angle-Side-Angle (ASA). Which segments are congruent by CPCTC?

Mathematics

1 answer:

Elis [28]2 years ago

8 0

Answer: AB ≅ CB

Step-by-step explanation:

In the given figure, we have ∆ABD ≅ ∆CBD

The CPCTC property of congruent triangles says that if two triangles are congruent then their corresponding parts ( angles and segments ) are congruent.

Since we have given that ∆ABD ≅ ∆CBD.

Therefore, the corresponding segments are congruent.

As segment AB is corresponding to segment CB. [First two letters]

Therefore, segment AB is congruent to segment CB.

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USPshnik [31]

A parallelogram is a quadrilateral in which opposite sides are equal, and the opposite angles sum up $180^{o}$ . Thus, the measures of the two different angles in the question are 70° and 110° i.e option D.

A parallelogram is a quadrilateral in which opposite sides are equal, and the opposite angles sum up $180^{o}$ . It has four straight sides and can be classified as a quadrilateral.

Thus from the given question, we have:

(6n − 70)° + (2n + 10)° = $180^{o}$

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i. (6n − 70)° = (6[30] − 70)°

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ii. (2n + 10)° = (2[30] + 10)°

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Therefore, the measures of the two different angles are 70° and 110°. Option D.

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Find the area of the surface. The surface with parametric equations x = u2, y = uv, z = 1 2 v2, 0 ≤ u ≤ 2, 0 ≤ v ≤ 1.

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Answer:

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Step-by-step explanation:

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Detailed description can be found in the attachment

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