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Diano4ka-milaya [45]
2 years ago
9

\sqrt[3]{1728} please help me with this

Mathematics
1 answer:
finlep [7]2 years ago
8 0
Prime factorization of 1728 is 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3
Simplifying the above expression: 26 × 33
Simplifying further: 123
Therefore, the cube root of 1728 by prime factorization is (2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3)1/3 = 12
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Is 7 a solution of 5x - 3 = 12?
V125BC [204]

Answer:

no

Step-by-step explanation:

5x - 3 = 12

5x=12+3

x=15/5=3

x=3

substitute x with 7 to find if it is a solution :

5(7)-3=12

35-3 ≠12 ( so no 7 is not a solution)

3 0
3 years ago
PLEASE THIS WAS DUE 2 WEEKS AGO I NEED HELP
Agata [3.3K]

Answer: C

Step-by-step explanation:

4 0
3 years ago
Write a x (-a)x 13 x a x (-a) x 13 in power notation
miss Akunina [59]

Answer:

a\times (-a)\times 13\times a\times (-a)\times 13 can be written in power notation as a^{4}\times 13^{2}

Step-by-step explanation:

The given expression

a\times (-a)\times 13\times a\times (-a)\times 13

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:

Let

a\times (-a)\times 13\times a\times (-a)\times 13

= [13\times13][(a\times (-a)\times a\times (-a)]

As

13\times13 = 13^{2} , a\times a = a^{2} , (-a)\times (-a) = (-a)^{2}

So,

=[13^{2}][a^2\times (-a)^2]

As

(-a)^2 = a^{2}

So,

=[13^{2}][a^2\times a^2]

As ∵a^{m} \times a^{n}=a^{m+n}

=[13^{2}][a^{2+2}]

As ∵a^{m} \times a^{n}=a^{m+n}

=13^{2}\times a^{4}

=a^{4}\times 13^{2}

Therefore, a\times (-a)\times 13\times a\times (-a)\times 13 can be written in power notation as a^{4}\times 13^{2}

<em>Keywords: power notation</em>

<em>Learn more about power notation from brainly.com/question/2147364</em>

<em>#learnwithBrainly</em>

5 0
3 years ago
Question:-
Reika [66]

{\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \bf \red{ \dfrac{1}{2} +  \dfrac{1}{4} =  \dfrac{3}{4}   }

Step by step explanation :-

The only thing you have to do is add the numerator to the denominator, in this case you have to add the first ones from the front, which can be these 2+1/4, which would result in 3/4, and this is called the Commutative Property.

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed{  \bf \gray{ \dfrac{1}{2} +  \dfrac{1}{4}  =  \dfrac{1}{4} +  \dfrac{1}{2}   }}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed{ \bf \green{\dfrac{2 + 1}{4}  =  \dfrac{1 + 2}{4} }}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed {\bf \blue{\dfrac{3}{4}  =  \dfrac{3}{4}} }

Answer :- The answer is 3/4

¿What is commutative property?

It is to change different ways in order of the addends the result would be the same.

Example :-

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed {\bf \blue{\dfrac{a}{b} + \dfrac{c}{d}} = {\dfrac{c}{d}  + \dfrac{a}{b}} }

I hope I've helped : )

5 0
2 years ago
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sergij07 [2.7K]
If you are given $10 every 3.5 hours and you want to find the unit rate per hour, you want to solve for how much money you make every hour. You do this by dividing the $10 by the 3.5 hours, which will result in about $2.86 per hour. (This is a rounded value)
5 0
3 years ago
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