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3 years ago

What is log base 6 of 15

Mathematics

1 answer:

sp2606 [1]3 years ago

3 0

Use the change of base formula:

log x

log to the base a of x = -----------

log a

Thus, log to the base 6 of 15 is as follows:

log 15

---------- (answer)

log 6

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Solve for x<br> (2^2/x) (2^4/x) = 2^12

earnstyle [38]

$\textsf{\qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

$\qquad \sf \dashrightarrow \:(2 {}^{ \frac{2}{x} } ) \sdot(2 {}^{ \frac{4}{x} } ) = 2 {}^{12}$

$\qquad \sf \dashrightarrow \:(2 {}^{ \frac{2}{x} + \frac{4}{x} } ) = 2 {}^{12}$

$\qquad \sf \dashrightarrow \:(2 {}^{ \frac{6}{x} } ) = 2 {}^{12}$

Now, since the base on both sides are equal, therefore their exponents are equal as well ~

$\qquad \sf \dashrightarrow \: \dfrac{6}{x} = 12$

$\qquad \sf \dashrightarrow \:x = \dfrac{6}{12}$

$\qquad \sf \dashrightarrow \:x = \dfrac{1}{2}$

$\qquad \sf \dashrightarrow \:x = 0.5$

Hope you got the required Answer ~

8 0

2 years ago

Find the difference of 67.2 and 23.9.

valentinak56 [21]

the difference of 67.2 and 23.9 is 43.3

8 0

3 years ago

Lyme disease is spread in the northeastern United States by infected ticks. The ticks are infected mainly by feeding on mice, so

Stels [109]

Answer: 90% confidence interval is; ( - 0.0516, 0.3752 )

Step-by-step explanation:

Given the data in the question;

n1 = 72, n2 = 17

P1 = 54 / 72 = 0.75

P2 = 10 / 17 = 0.5882

P_good = 0.75

P_bad = 0.5882

standard ERRROR will be;

SE = √[(0.75×(1-0.75)/72) + (0.5882×(1-0.5882)/17)]

SE = √( 0.002604 + 0.01424)

SE = 0.12978

given confidence interval = 90%

significance level a = (1 - 90/100) = 0.1, |Z( 0.1/2=0.05)| = 1.645 { from standard normal table}

93% CI is;

(0.75 - 0.5882) - 1.645×0.12978 <P_good - P_bad< (0.75 - 0.5882) + 1.645×0.12978

⇒0.1618 - 0.2134 <P_good - P_bad< 0.1618 + 0.2134

⇒ - 0.0516 <P_good - P_bad< 0.3752

Therefore 90% confidence interval is; ( - 0.0516, 0.3752 )

4 0

3 years ago

You have 3 online accounts in three different banks valued at: bank "A" = $250.67, 12% interest, bank "B" $765.13, 7% interest,

gregori [183]

Answer:

$\$882.89$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

Bank A

$t=1\ years\\ P=\$250.67\\r=12\%=12/100=0.12$

substitute in the formula above

$I=250.67(0.12*1)=\$30.08$

Bank B

$t=1\ years\\ P=\$765.13\\r=7\%=7/100=0.07$

substitute in the formula above

$I=765.13(0.07*1)=\$53.56$

Bank C

$t=1\ years\\ P=\$28,500.36\\r=9\%=9/100=0.09$

substitute in the formula above

$I=28,500.36(0.09*1)=\$2,565.03$

Find the average interest gained from the three accounts in one year

$[\$30.08+\$53.56+\$2,565.03]/3=\$882.89$

3 0

3 years ago

Which graph represents the function f(x) = 1/3|x| ?

adelina 88 [10]

The bottom graph! :)

3 0

3 years ago

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