Answer:
You will have 14 gallons of paint left over.
Step-by-step explanation:
If you divide a mural into 6 sections, and paint each section with 3 gallons of paint per section, that means you are using 3 gallons of paint 6 times.
3 x 6 = `18
Therefore, you will be using 18 gallons of paint for the mural, and when you subtract 18 gallons from the original 32 gallons of paint, you get 14 gallons left over.
Answer:
- 0.092g
- 0.979g
- 0.983g
Explanation: 0.83 > 0.979 > 0.092
The answer is on the picture below
The answer is A.
The way you know this is by graphing the first function.
The second function is in a different format, so you just have to isolate Y.
-1/3x + y = -1
y= 1/3x -1 OR y= -1 + 1/3x
both of the functions have the same slope, but different y-intercepts. therefore, they'll never touch. making them infinite solutions.
it's also A because both of the slopes are positive, the slopes in graph D are negative.
So, the answer is A.
Hope this helps! xx
9514 1404 393
Answer:
a) V = 4w²h
b) SA = 4w² +10wh
c) SA = 4w² +37.5/w
d) C = 40w² +225/w
Step-by-step explanation:
The relevant formulas are ...
V = LWH
base area = LW
lateral area = H(2(L+W))
__
a) The length is 4 times the width, so the volume is ...
V = (4w)(w)(h)
V = 4w²h
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b) The total surface area is the sum of the base area and the lateral area:
SA = base area + lateral area
SA = (4w)(w) + 2h(4w +w)
SA = 4w² +10wh
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c) The volume is 15 m³, so the height in meters in terms of the width in meters is ...
15 = 4w²h
h = 15/(4w²)
Then the surface area is ...
SA = 4w² +10w(15/(4w²))
SA = 4w² +37.5/w
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d) The equation we have for surface area has one term for base area and a second term for lateral area. We can apply the cost factors to those terms to get the cost of materials:
C = 10(4w²) +6(37.5/w)
C = 40w² +225/w
