A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
The z-score tells you how many standard deviations from the mean.
<span>1.5 * 3.6 = 5.4 miles </span>
<span>So anything within 5.4 miles of the average (29). </span>
<span>The range would be: </span>
<span>29 - 5.4 = 23.6 </span>
<span>to: </span>
<span>29 + 5.4 = 34.4 </span>
<span>23.6 ≤ x ≤ 34.4 </span>
<span>Answer: </span>
<span>B) 24 miles</span>
Answer:
i cant telll bc theres no picture
Answer: the box contained 9 square chocolates and 15 round chocolates.
Step-by-step explanation:
Let x represent the number of square chocolates contained in the box.
Let y represent the number of round chocolates contained in the box.
The box of chocolates contains square chocolates, which weigh 10g each and round chocolates which weigh 8g each. The combined weight of all the chocolates is 210g. It means that
10x + 8y = 210- - - - - - - - - - -1
The number of round chocolates is 3 less than twice the number of square chocolates. It means that
y = 2x - 3
Substituting y = 2x - 3 into equation 1, it becomes
10x + 8(2x - 3) = 210
10x + 16x - 24 = 210
26x = 210 + 24
26x = 234
x = 234/26
x = 9
y = 2x - 3 = 2 × 9 - 3
y = 18 - 3
y = 15
