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3 years ago

– 72 = 3(- 4x – 8) Need help

Mathematics

1 answer:

Finger [1]3 years ago

8 0

Answer:

x = 4

Step-by-step explanation:

Step 1: Write equation

-72 = 3(-4x - 8)

Step 2: Solve for <em>x</em>

<u>Distribute 3:</u> -72 = -12x - 24

<u>Add 24 to both sides:</u> -48 = -12x

<u>Divide both sides by -12:</u> x = 4

Step 3: Check

<em>Plug in x to verify if it's a solution.</em>

-72 = 3(-4(4) - 8)

-72 = 3(-16 - 8)

-72 = 3(-24)

-72 = -72

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Answer:

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Step-by-step explanation:

2 plus 2 is 4

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3 years ago

Add or Subtract to Simplify:<br> (4x - 2x3) + (5x3 - 4x + 5)

sukhopar [10]

Answer:

Step-by-step explanation:

( 4x - 2x³ ) + ( 5x³ - 4x + 5)

<u>Remove the parenthesis</u>

That's

4x - 2x³ + 5x³ - 4x + 5

<u>Group like terms</u>

We have

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3 years ago

7y-12-3y+9=0 help please

nasty-shy [4]

Simplify. Combine like terms

7y - 3y = 4y

-12 + 9 = -3

----------------------------------------------------------------------------------------------------------------

4y - 3 = 0

Isolate the y. Note the equal sign. What you do to one side, you do to the other side. Do the opposite of PEMDAS.

4y - 3 (+3) = 0 (+3)

4y = 3

4y/4 = 3/4

y = 3/4

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y = 3/4 is your answer

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hope this helps

3 0

3 years ago

Read 2 more answers

What number lies between 7x8/10=

zzz [600]

The number that lies between that is 7

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3 years ago

Read 2 more answers

Try this hard Math Problem if you dare!!

Dennis_Churaev [7]

Answer:

a. $(x - 3)^2 + 16$

b. $8(x -7)^2$

c. $(a^2 - 1)(7x - 6)$ or $(a+1)(a-1)(7x-6)$

d. $(x^2-4)(x^2+3)$ or $(x-2)(x+2)(x^2+3)$

e. $(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

Step-by-step explanation:

$a.\ (x + 1)^2 - 8(x - 1) + 16$

Expand

$(x + 1)(x + 1) - 8(x - 1) + 16$

Open brackets

$x^2 + x + x + 1 - 8x + 8 + 16$

$x^2 + 2x + 1 - 8x + 24$

Collect Like Terms

$x^2 + 2x - 8x+ 1 + 24$

$x^2 - 6x+ 25$

Express 25 as 9 + 16

$x^2 - 6x+ 9 + 16$

Factorize:

$x^2 - 3x - 3x + 9 + 16$

$x(x -3)-3(x - 3) + 16$

$(x - 3)(x - 3) + 16$

$(x - 3)^2 + 16$

$b.\ 8(x - 3)^2 - 64(x-3) + 128$

Expand

$8(x - 3)(x - 3) - 64(x-3) + 128$

$8(x^2 - 6x+ 9) - 64(x-3) + 128$

Open Brackets

$8x^2 - 48x+ 72 - 64x+192 + 128$

Collect Like Terms

$8x^2 - 48x - 64x+192 + 128+ 72$

$8x^2 -112x+392$

Factorize

$8(x^2 -14x+49)$

Expand the expression in bracket

$8(x^2 -7x-7x+49)$

Factorize:

$8(x(x -7)-7(x-7))$

$8((x -7)(x-7))$

$8(x -7)^2$

$c.\ 7a^2x - 6a^2 - 7x + 6$

Factorize

$a^2(7x - 6) -1( 7x - 6)$

$(a^2 - 1)(7x - 6)$

The answer can be in this form of further expanded as follows:

$(a^2 - 1^2)(7x - 6)$

Apply difference of two squares

$(a+1)(a-1)(7x-6)$

$d.\ x^4 - x^2 - 12$

Express $x^4$ as $x^2$

$(x^2)^2 - x^2 - 12$

Expand

$(x^2)^2 +3x^2- 4x^2 - 12$

$x^2(x^2+3) -4(x^2+3)$

$(x^2-4)(x^2+3)$

The answer can be in this form of further expanded as follows:

$(x^2-2^2)(x^2+3)$

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Represent as squares

$(a^{2n})^2 -(b^{2n})^2$

Apply difference of two squares

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Represent as squares

$((a^{n})^2 -(b^{n})^2)(a^{2n} +b^{2n})$

Apply difference of two squares

$(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

6 0

3 years ago