Question

The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle​

Answer 1

Answer:

• Length of rectangle is 31 yards and Width is 24 yards.

Given:

• The length of a rectangle is 7 more than the width.
• The area is 744 sqaure yards

Solution:

Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.

Using formula

$\\ \: \: \: \: \pink{ \dashrightarrow \: \: \: \: \sf { \underbrace{Area_{(Rectangle)} = Length × Width }}}$

On Substituting the required values, we get;

$\\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x = 24 \: or \: - 31$

As we know that width of the rectangle can't be negative. So x = 24

Hence,

• Width of rectangle = x = 24 yards
• Length of the rectangle = x + 7 = 31 yards

$\therefore$Length of rectangle is 31 yards and Width is 24 yards.