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2 years ago

Find g(-3) g(2) g(4)

Mathematics

1 answer:

Stells [14]2 years ago

4 0

Answer:

$\frac{1}{2}$ , 2 , 4

Step-by-step explanation:

x = - 3 ≠ 2 , then

g(- 3) = $\frac{1}{2}$ × (- 3)² - 4 = $\frac{1}{2}$ × 9 - 4 = $\frac{9}{2}$ - 4 = $\frac{1}{2}$

x = 2 then g(2) = 2

x = 4 ≠ 2 , then

g(4) = $\frac{1}{2}$ × 4² - 4 = $\frac{1}{2}$ × 16 - 4 = 8 - 4 = 4

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$\qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star$

[ b ] is the Correct one

$\textsf{ \underline{\underline{Steps to solve the problem} }:}$

$\qquad❖ \: \sf \:4 \: log_{3}(y) - 6 \: log_{3}(x) + 7 \: log_{3}(z)$

$\qquad❖ \: \sf \: \: log_{3}(y {}^{4} ) - \: log_{3}(x {}^{6} ) +\: log_{3}(z {}^{7} )$

$\qquad❖ \: \sf \: \: log_{3}(y {}^{4} ) + \: log_{3}(z{}^{7} ) - \: log_{3}(x {}^{6} )$

( $\sf a\: log (b) = log {b}^{a}$ )

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( $\sf{log (a) + log (b) = log (ab)}$ )

$\qquad❖ \: \sf \: log_{3} \bigg( \dfrac{y {}^{4} {z}^{7} }{ {x}^{6} } \bigg )$

( $\sf{log (a) - log (b) = log (a/b)}$ )

$\qquad \large \sf {Conclusion} :$

[ b ] is the Correct choice

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