Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
Answer:
4760
Step-by-step explanation:
First you find out how many are in a dollar so you do
119*4 which is 476
Then because there is $10 you need to do
476 * 10 which would be 4760
Answer:
I think it's right answer is 530
Answer:
hey! This was the only part of mathematics I ever enjoyed! So consider this both of our lucky days: Answer is : (2,7)
Step-by-step explanation:
basically plug in Y to the first equation as sox + 4(-x + 9) = 30
x - 4x + 36 = 30- 3x = - 6
x = 2
then plug that in to Y!
Y = -(2) + 9
so Y = 7
and our answer is : (2,7)
Bases+faces=surface area
15.6+81=96.6
Because 1/2*6*9=27*3=81