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2 years ago

In a 30-60-90 triangle the long leg is half the hypotenuse.

2 answers:

7 0

And because we know that we cut the base of the equilateral triangle in half, we can see that the side opposite the 30° angle (the shortest side) of each of our 30-60-90 triangles is exactly half the length of the hypotenuse.

Masja [62]2 years ago

4 0

Answer:

Never

Step-by-step explanation:

In a 30°−60°−90° triangle, the length of the hypotenuse is twice the length of the shorter leg, and the length of the longer leg is √3 times the length of the shorter leg. To see why this is so, note that by the Converse of the Pythagorean Theorem, these values make the triangle a right triangle.

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You deposit $1500 into a savings account that pays 6% interest compounded yearly. How much money is in the account after 10 year

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3 years ago

Read 2 more answers

Mark drew two triangles and 8 arrows as part of a set of 13 shapes. The only other type of shape in the set is a circle. What fr

luda_lava [24]

Answer:

3/13

Step-by-step explanation:

First...

What we know

1. There is a set of 13 shapes.

2. With 2 triangles, 8 arrows, and circles.

Next...

Take the number of triangles and arrows and add them up.

2 + 8 = 10

Finally...

Convert it into the fraction 10/13 and subtract it by the total 13/13.

This results 3/13.

3 0

3 years ago

Answer these 2 questions please

Whitepunk [10]

Hi there!

Question 1:

For this, we are taking away 1/4 yards of spring from 7/8 yards. This is essentially just subtracting 1/4 from 7/8. This then gives us the equation:

$\frac{7}{8}-\frac{1}{4}$

Now, to subtract these, we want to make it so the denominators are the same, or the numbers on the lower half are the same. (One way to explain why this is true is: $\frac{a}{b}-\frac{c}{b}=a\frac{1}{b}-c\frac{1}{b}=(a-c)\frac{1}{b}=\frac{a-c}{b}$ ). Now, to make it so the denominators are the same, we can multiply the second fraction, 1/4, by 2/2 as 2/2 is essentially 1, and multiplying by 1 will get the same result, just with a denominator switched in this case. Doing this, we get:

$\frac{7}{8}-\frac{1}{4}\cdot\frac{2}{2}$

$\frac{7}{8}-\frac{2}{8}$

Now, subtracting the numerators, we get:

$\frac{5}{8}$ yards of string will remain.

Question 2:

For this, we are combining these two thicknesses, and thus we add 1/4 to 7/12. This gives us the equation:

$\frac{1}{4}+\frac{7}{12}$

Now, we again want to make it so the denominators are the same. (Here's a similar proof but for addition this time: $\frac{a}{b}+\frac{c}{b}=a\frac{1}{b}+c\frac{1}{b}=(a+c)\frac{1}{b}=\frac{a+c}{b}$ ). Now, to make the denominators the same, we can multiply the first fraction, 1/4, by 3/3 (also equivalent to 1). Doing this, we get: