Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
Answer: total comes to 4X - 12Y + 4
Step-by-step explanation:
I hope this helps you
Area=length ×width
30 1/3=30.3+1/3=91/3
6 1/2=6.2+1/2=13/2
91/3=13/2.width
width =7.13.2/3.13
width =14/3
width = 4 2/3
Answer:
its 3
Step-by-step explanation:
selcet 3 it goes plus 3 then back to neg 4 its the 3rd option
True I believe my friend.
