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sesenic [268]
3 years ago
9

The points (-1,1), (0,0), and (1,1) translate the points __ of g(x).

Mathematics
1 answer:
wariber [46]3 years ago
8 0
The answer would be -1,2
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What is the solution to this -28=3+8(h-9)??
stiks02 [169]
-28 = 3 + 8(h-9)
-28 = 3 + 8h - 72    (distributive property a(b-c) = ab - ac)
-28 = -69 + 8h        (combining like terms ( 3 - 72))
 41 = 8h                  (adding 69 on both sides to isolate 8h)
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3 years ago
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ser-zykov [4K]

Answer:

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(x-a)^2+(y-b)^2=r^2

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(x+3)^2+(y+2)^2=r^2

We know the circle passes through the origin. This means that the equation above holds for x=0 and y=0. The distance between any point on the circle and its center is the radius, so we can use this fact to determine r:

(0+3)^2+(0+2)^2=r^2\implies 9+4=13=r^2\implies r=\sqrt{13}

So the circle's equation is

(x+3)^2+(y+2)^2=(\sqrt{13})^2=13

b. If the distance between point B and the center is less than \sqrt{13}, then B lies inside the circle. If the distance is greater than \sqrt{13}, it falls outside the circle. Otherwise, if the distance is exactly \sqrt{13}, then B lies on the circle.

The distance from B to the center is

\sqrt{(-1+3)^2+(3+2)^2}=\sqrt{4+25}=\sqrt{29}

29>13, so \sqrt{29}>\sqrt{13}, which means B falls outside the circle.

5 0
3 years ago
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3 years ago
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How is the graph of y=-2x^2-5 different from the graph of y=-2x^2?
ki77a [65]
In the first equation graph will touch x axis because equation have x intercept but in the 2nd equation graph will not touch the x axis. BECAUSE it doesn't have x intercept.
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